07-08-2006
Thanks grumpf,
Actaully i was looking for some similar options if i could..But the problem is I am using SunOs 5.8 and i am not authorized to add any package to the server.I tried this command and it didn't work..
It seems you have done lot of stuff on date command,Can you tell me is there any way to use date command to read from some variable not from the system,I mean if i can give my inputs to date command with out disturbing any system configurations?
Thanks in advance..
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
i need to grep date in the format year-month-day,,,,,,,
actually i need to grep those dates other than current date..........
can anyone help me in this...........i need a format of date which would grep previous date except current date (1 Reply)
Discussion started by: ali560045
1 Replies
2. Shell Programming and Scripting
I am writing an shell script , which reads a file with contents
Example :: (( This Format is yyyy-MM-DD))
2008-05-16
2008-05-17
2008-05-18
2008-05-19
2008-05-20
2008-05-21
when i run the shell script it has to check the current date and compare it with the todays date and give me... (24 Replies)
Discussion started by: ranga27
24 Replies
3. UNIX for Dummies Questions & Answers
How can i assign a variable by the name of CUTDATE= today date - 90 days? i have something like this right now :-
today=`date '+%Y%m%d'`
#cutdate = this is where i am having problem. i need today - 90 days
How can i accomplish this? After that i need to do delete the data which are more... (16 Replies)
Discussion started by: chris1234
16 Replies
4. Shell Programming and Scripting
Hi Friends,
Need a command/script in unix which calculates previous date from current date.
For ex:
If current date= 01 Jan 2008, then output =31 Dec 2007
If current_date =01 Aug 2008 , then output= 31 July 2008
Please advice
Regards,
Suresh (3 Replies)
Discussion started by: sureshg_sampat
3 Replies
5. Shell Programming and Scripting
Hi all,
this is my first post, i need to write a script to zip the files with datewise below are the log files.
-rw------- 1 root sso 85316156 May 24 22:11 core_test_smservaz_104_104_1243217459_8896
-rw------- 1 root sso 90413304 May 25 22:12 core_test_smservaz_104_104_1243303895_20912... (4 Replies)
Discussion started by: lcschandu
4 Replies
6. UNIX for Dummies Questions & Answers
Hi All,
I was trying to get the date in format "Feb2" I tried
option "e" giving me a padded space and getting the result as "Feb 2". Though its working fine for dates 10 to 31.
Please suggest me how to get rid of this space before date.
Thanks
Olivia (4 Replies)
Discussion started by: Olivia
4 Replies
7. Shell Programming and Scripting
I have a file (main.lst) containing a list of dates in DDMMYYYY format. The dates will mostly be the same but it is possible to have multiple dates and these need not be in chronological order. I have another file containing another list of dates (holidays.lst).
The task is to get the latest... (5 Replies)
Discussion started by: elixir_sinari
5 Replies
8. Shell Programming and Scripting
We have year folder say in a path /opt/informat/Archive a folder 2012.
And in the same folder /opt/informat/Archive we have different folders month based, like 201210, 201211, 201212, this have data for each month, ie files. Now time to time i need to move the monthly folders to the main folder... (1 Reply)
Discussion started by: raghavraok
1 Replies
9. Shell Programming and Scripting
Hello,
I have this unix script which selects rows from DB where current time is greater than expired time (column). So this will give all the records that are expired 1 day ago, 2 days ago, 3 days ago, etc.. I need help modifying in such that it should give records that are only expired 1 day... (5 Replies)
Discussion started by: jakSun8
5 Replies
10. Shell Programming and Scripting
How to create a shell script to create a folder by using the today's date to take backup using rsync command on every evening around 7 pm.
Kindly help.
Thanks.
To be more precise,
I want to create a script which matches the today's date with server's date format, if matches then creates the... (2 Replies)
Discussion started by: bakula10
2 Replies
cal(1) User Commands cal(1)
NAME
cal - display a calendar
SYNOPSIS
cal [ [month] year]
DESCRIPTION
The cal utility writes a Gregorian calendar to standard output. If the year operand is specified, a calendar for that year is written. If
no operands are specified, a calendar for the current month is written.
OPERANDS
The following operands are supported:
month Specify the month to be displayed, represented as a decimal integer from 1 (January) to 12 (December). The default is the current
month.
year Specify the year for which the calendar is displayed, represented as a decimal integer from 1 to 9999. The default is the current
year.
ENVIRONMENT VARIABLES
See environ(5) for descriptions of the following environment variables that affect the execution of cal: LANG, LC_ALL, LC_CTYPE, LC_TIME,
LC_MESSAGES, and NLSPATH.
TZ Determine the timezone used to calculate the value of the current month.
EXIT STATUS
The following exit values are returned:
0 Successful completion.
>0 An error occurred.
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWesu |
+-----------------------------+-----------------------------+
|Interface Stability |Standard |
+-----------------------------+-----------------------------+
SEE ALSO
calendar(1), attributes(5), environ(5), standards(5)
NOTES
An unusual calendar is printed for September 1752. That is the month 11 days were skipped to make up for lack of leap year adjustments. To
see this calendar, type:
cal 9 1752
The command cal 83 refers to the year 83, not 1983.
The year is always considered to start in January.
SunOS 5.10 1 Feb 1995 cal(1)