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Top Forums UNIX for Dummies Questions & Answers shell help - file combination Post 302077925 by ting123 on Tuesday 27th of June 2006 04:59:03 PM
Old 06-27-2006
shell help - file combination

Dear all,

I have a question about merging multiple files to one.

For example, I have 4 files, named file_1, file_2, file_3 and file_4, they all have same line number, and only one word in each line. I want to combine these four files to one file, file_1 becomes the first column of the new file, and file_2 becomes the second column of the new file, and so on.

How can I use shell to do this?

Thanks in advance.
 

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PASTE(1)						      General Commands Manual							  PASTE(1)

NAME
paste - paste multiple files together SYNOPSIS
paste [-s] [-d list] file... OPTIONS
-d Set delimiter used to separate columns to list. -s Print files sequentially, file k on line k. EXAMPLES
paste file1 file2 # Print file1 in col 1, file2 in col 2 paste -s f1 f2 # Print f1 on line 1 and f2 on line 2 paste -d : file1 file2 # Print the lines separated by a colon DESCRIPTION
Paste concatenates corresponding lines of the given input files and writes them to standard output. The lines of the different files are separated by the delimiters given with the option -s. If no list is given, a tab is substituted for every linefeed, except the last one. If end-of-file is hit on an input file, subsequent lines are empty. Suppose a set of k files each has one word per line. Then the paste output will have k columns, with the contents of file j in column j. If the -s flag is given, then the first file is on line 1, the second file on line 2, etc. In effect, -s turns the output sideways. If a list of delimiters is given, they are used in turn. The C escape sequences , , \, and are used for linefeed, tab, backslash, and the null string, respectively. PASTE(1)
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