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UNIX for Dummies Questions & Answers
question about printing number of lines in a file
Post 28275 by Kelam_Magnus on Monday 16th of September 2002 02:20:19 PM
09-16-2002
use grep instead of cat...
You can also use:
grep -v ^$ file.in |wc -l
^ denotes the beginning of the line $ denotes the end of the line. When put together with grep -v, they elimnate the blank lines!!
Using cat is an extra step. This is a little more efficient with 2 commands instead of three. Brevity is a programmer's friend.
grep -v ^$ file.in |wc -l
^ denotes the beginning of the line $ denotes the end of the line. When put together with grep -v, they elimnate the blank lines!!
Using cat is an extra step. This is a little more efficient with 2 commands instead of three. Brevity is a programmer's friend.
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LEARN ABOUT PHP
zgrep
ZGREP(1) General Commands Manual ZGREP(1) NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)