09-16-2002
Zero Padding to a string
I am writing a C program which a part of it needs to padding zero in front of a string. The program will get a sting from an ASCII file which the maxium length of this string is 5 char long. The string can sometimes less the 5 char long. In order to make it with the same length '0's are being pad in front ot the string.
e.g. if the string from the ASCII file is '123 ' then 2 '0's will be needed in front which will make it look like this '00123'
Can someone help me with that...... I am totally new to C programming. I think for someone with a little bit C language experience it should be quit strict forward, or is it.
Thanks
Vincent
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A64L(3) Linux Programmer's Manual A64L(3)
NAME
a64l, l64a - convert between long and base-64
SYNOPSIS
#include <stdlib.h>
long a64l(char *str64);
char *l64a(long value);
DESCRIPTION
These functions provide a conversion between 32-bit long integers and little-endian base-64 ASCII strings (of length zero to six). If the
string used as argument for a64l() has length greater than six, only the first six bytes are used. If longs have more than 32 bits, then
l64a() uses only the low order 32 bits of value, and a64l() sign-extends its 32-bit result.
The 64 digits in the base 64 system are:
'.' represents a 0
'/' represents a 1
0-9 represent 2-11
A-Z represent 12-37
a-z represent 38-63
So 123 = 59*64^0 + 1*64^1 = "v/".
NOTES
The value returned by a64l() may be a pointer to a static buffer, possibly overwritten by later calls.
The behaviour of l64a() is undefined when value is negative. If value is zero, it returns an empty string.
These functions are broken in glibc before 2.2.5 (puts most significant digit first).
CONFORMING TO
XPG 4.2, POSIX 1003.1-2001.
SEE ALSO
uuencode(1), itoa(3), strtoul(3)
2002-02-15 A64L(3)