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Top Forums UNIX for Dummies Questions & Answers pulling the following line from a file Post 27257 by Perderabo on Thursday 29th of August 2002 08:21:05 AM
Old 08-29-2002
How about:
sed -n '/^11/{;p;n;p;q;}'

This assumes that want only the first couplet that starts with 11. To get them all, omit "q;".
 

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PINKY(1)							   User Commands							  PINKY(1)

NAME
pinky - lightweight finger SYNOPSIS
pinky [OPTION]... [USER]... DESCRIPTION
-l produce long format output for the specified USERs -b omit the user's home directory and shell in long format -h omit the user's project file in long format -p omit the user's plan file in long format -s do short format output, this is the default -f omit the line of column headings in short format -w omit the user's full name in short format -i omit the user's full name and remote host in short format -q omit the user's full name, remote host and idle time in short format --help display this help and exit --version output version information and exit A lightweight 'finger' program; print user information. The utmp file will be /var/run/utmp. AUTHOR
Written by Joseph Arceneaux, David MacKenzie, and Kaveh Ghazi. REPORTING BUGS
GNU coreutils online help: <http://www.gnu.org/software/coreutils/> Report pinky translation bugs to <http://translationproject.org/team/> COPYRIGHT
Copyright (C) 2017 Free Software Foundation, Inc. License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>. This is free software: you are free to change and redistribute it. There is NO WARRANTY, to the extent permitted by law. SEE ALSO
Full documentation at: <http://www.gnu.org/software/coreutils/pinky> or available locally via: info '(coreutils) pinky invocation' GNU coreutils 8.28 January 2018 PINKY(1)
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