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Full Discussion: A Simple shell Script
Top Forums Shell Programming and Scripting A Simple shell Script Post 11391 by Jamie Bell on Tuesday 4th of December 2001 01:09:07 PM
Old 12-04-2001
Finding and counting files

Try these ideas...

1. Count all instances of a specified file name in the file system:

ls -a | grep -c filename

The ls -a will list all files including the dot-files (the -a arg).
Piping to grep -c will count (the -c arg) the hits on filename in
the output of ls -a.

I don't know how to execute that recursively from the
root all the way throughout every directory in the system.


2. List all occurances of a file name:

ls -a | grep filename
 

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ZGREP(1)                                                      General Commands Manual                                                     ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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