#! /usr/bin/ksh
year=$1
month=$2
week=$3
day=$4
set -A days Sun Mon Tue Wed Thu Fri Sat
set -A months XXX Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec
cal $month $year
#
# Get date of last day in 1st week of month
dldw1=$(cal $month $year | sed -n '3s/. //gp')
#
# calculate what day-of-month is day/week
if [[ $week = 1 ]] ; then
((dom=day))
else
((dom=day+dldw1+((week-2)*7)))
fi
#
# Calculate day of week
((dow = (dom+dldw1)%7 ))
#
# All done...print it out
echo ${months[month]} ${dom}, $year is on ${days[dow]}
exit 0
Hi,
I posted something here about this yesterday but I can't seem to
find it. I needed help writting a script which would append a file
with new lines after every so many charachters.
Example: (my original flat file)
L60 LETTER OF CREDIT 60 DAYS W00 ON RECEIPT WIRE TRANSFER W30 NET... (12 Replies)
Hi All,
How can i store a value of the unix command executed in AWK with system command.
devise=`cut -c1-3 dvgp.txt`
I wrote this command in awk as
awk'{
code= sprintf("devise=`cut -c1-3 dvgp.txt`");
system(code);
}'
Is this correct. can you please suggest me how the code can be... (1 Reply)
Hi there every body
I'm new to shell scripting and there is a problem facing me,, please look at the following piece of code:
awk '
BEGIN{
FS="<assertion id=\1";
RS="<assertion id=\"2"}/<assertion id=\"1/{print FS$2 > "/home/ds2/test/output.txt"}
' filename
all I wanna do is to... (6 Replies)
Actually I got a list of file end with *.txt
I want to use the same command apply to all the *.txt
Thus I try to find out the fastest way to write those same command in a script and then want to let them run automatics.
For example:
I got the file below:
file1.txt
file2.txt
file3.txt... (4 Replies)
Hi
I have many problems with a script. I have a script that formats a text file but always prints the same error when i try to execute it
The code is that:
{
if (NF==17){
print $0
}else{
fields=NF;
all=$0;
while... (2 Replies)
Find the number of files with sizes > 100KB in /, /bin, /usr, /usr/bin
and /usr/sbin directories and output them in a two column format with the
name of the directory and the number of files.
i tried with awk
$>ls -lh | awk '/^-/ && $5 >= 100k {print $8 $5}'
but it is not working pls tell... (3 Replies)
I thought I had solved this problem but after testing the script I came to realize that it is not doing what I need. So, here it goes again. This is the code:
awk '/\>/{F=$2; N=$3; split(FILENAME, A, "."); getline; x = ">"}{print ">" A"-" x++" "F" " N"\n" $0}'
This is the input file:
... (5 Replies)
i have a datafile that has several lines that look like this:
2,dataflow,Sun Mar 17 16:50:01 2013,1363539001,2990,excelsheet,660,mortar,660,4
using the following command:
awk -F, '{$3=strftime("%a %b %d %T %Y,%s",$3)}1' OFS=, $DATAFILE | egrep -v "\-OLDISSUES," | ${AWK} "/${MONTH} ${DAY}... (7 Replies)
i have an email list in file.txt with comma separated
line1 - FIELD1,pippo@gmail.com,darth@gmail.com
line2 - FIELD2,pippo@gmail.com,darth@gmail.com,sampei@gmail.com
output=(awk -F ',' -v var="$awkvar" '$1==var {print $2,$3,$4}' spreadsheet.txt)but awk delete some letters at the... (8 Replies)
Hi
I have two columns and I would like to create a third column based on how many lines away from a value of 1 in column 2,
for example I have
1,0
2,0
3,0
4,0
5,0
6,1
7,0
8,0
9,0
10,0
11,1
And I want an output (6 Replies)
Discussion started by: garethsays
6 Replies
LEARN ABOUT SUSE
cal
CAL(1) BSD General Commands Manual CAL(1)NAME
cal -- displays a calendar
SYNOPSIS
cal [-smjy13] [[[day] month] year]
DESCRIPTION
Cal displays a simple calendar. If arguments are not specified, the current month is displayed. The options are as follows:
-1 Display single month output. (This is the default.)
-3 Display prev/current/next month output.
-s Display Sunday as the first day of the week.
-m Display Monday as the first day of the week.
-j Display Julian dates (days one-based, numbered from January 1).
-y Display a calendar for the current year.
-V Display version information and exit.
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: ``cal 89'' will not display a calen-
dar for 1989. Two parameters denote the month (1 - 12) and year. Three parameters denote the day (1-31), month and year, and the day will
be highlighted if the calendar is displayed on a terminal. If no parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's.) Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
OTHER VERSIONS
Several much more elaborate versions of this program exist, with support for colors, holidays, birthdays, reminders and appointments, etc.
For example, try the cal from http://home.sprynet.com/~cbagwell/projects.html or GNU gcal.
AVAILABILITY
The cal command is part of the util-linux-ng package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux-ng/.
BSD June 6, 1993 BSD