An other awk problem

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# 1  
Old 11-23-2001
An other awk problem

Hi all...

Smilie Smilie Smilie

I'm looking for a way to get the nth day of mth week of a month based on the "cal" command:
Meaning the following:
$ cal 11 2001|cat -n
1 November 2001
2 S M Tu W Th F S
3 1 2 3
4 4 5 6 7 8 9 10
5 11 12 13 14 15 16 17
6 18 19 20 21 22 23 24
7 25 26 27 28 29 30

What i want, is to say " I want the 3rd day of week 4 ( with the cat -n that would be 6).
I'm looking for a comand using the awk command

looking something like:
cal 11 2001|cat -n|grep "my_week( here is 6)"|awk 'my function of awk ', so the output would be:
tuesday 20th november...

Thanx for your help...

Have a nice week-end!

# 2  
Old 11-23-2001
Try this...
#! /usr/bin/ksh


set -A days Sun Mon Tue Wed Thu Fri Sat
set -A months XXX Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec
cal $month $year

# Get date of last day in 1st week of month
dldw1=$(cal $month $year | sed -n '3s/. //gp')

# calculate what day-of-month is day/week
if [[ $week = 1 ]] ; then

#  Calculate day of week

((dow = (dom+dldw1)%7 ))

#  All done...print it out

echo ${months[month]} ${dom}, $year is on ${days[dow]} 

exit 0

# 3  
Old 11-25-2001
Nice code, Perderabo.

Here is an awk solution:


export month week day

cal $month $year | cat -n |
awk -v m=$month -v w=$week -v d=$day \
   'BEGIN {split("Jan Feb ... Nov Dec",mo)
           split("Sun Mon Tue Wed Thu Fri Sat",dow)}
    NF>1&&$1==w+2 {
       if (d>=NF)
           print "non-existant day of week"
           print dow[d+8-NF], mo[m], $(d+1)}'

You need to expand the month array where I have "...". I am assuming that when week 1 starts on Thursday, then Thursday would be day 1.

Output format is: Tue Nov 20

added code tags for readability --oombera

Last edited by oombera; 02-20-2004 at 12:41 PM..
# 4  
Old 11-27-2001
Do you want to try my shorter pipe ?

[for ksh clones]

let line=week+2

cal 11 2001 | head -$line| tail -1| cut -f$day_of_week -d " "
# 5  
Old 11-27-2001
Thanx for your help...

Is there a way using awk, that would give something like
cal $month $year|cat -n | awk '{print $(NF-$a_variable)}', where i could precise a_variable?
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