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Full Discussion: UNIX CGI script
Top Forums UNIX for Dummies Questions & Answers UNIX CGI script Post 10175 by primal on Thursday 8th of November 2001 10:17:18 PM
Old 11-08-2001
Question UNIX CGI script

Hey everyone!
I hope someone here is good with Unix CGI scripts.
I'm having trouble with my CGI. Here's the deal

I've created a program that searches the passwd file and cuts the users real name when it's given the login name. When i converted it to CGI i ran into some problems:

1) when you put one login name in, it echo's a statement (user is online/offine) 6 times! BUT when you put 2 or more, there is no repeating.

2) i dont think $* works when doing for loop. i had to hard code up to 6 variables (could be more though)

can anyone offer any help? I also ported this into an HTML version, but still have the same problems. (could have swore i had this working, but when i saved the HTML one, i over wrote the working one, and i forgot what changed i made Smilie )
I think it's my quotes but i'm not really sure anymore lol

here's my code:
Code:
#!/bin/sh

echo "Content-Type: text/plain"
echo ""

slice=`echo $QUERY_STRING|cut -d= -f2`

if [ "$slice" = "" ]; then
   echo Please go back and enter a login name
fi

name1=`echo $slice|cut -d+ -f1`
name2=`echo $slice|cut -d+ -f2`
name3=`echo $slice|cut -d+ -f3`
name4=`echo $slice|cut -d+ -f4`
name5=`echo $slice|cut -d+ -f5`
name6=`echo $slice|cut -d+ -f6`
names="$name1 $name2 $name3 $name4 $name5 $name6"

for name in $names
do
   who | grep $name > /dev/null

   if [ $? = "0" ]; then
      echo "Yes `grep "$name" /etc/passwd | cut -f5 -d:` is online"
   else
      echo "No `grep "$name" /etc/passwd | cut -f5 -d:` is offline"
   fi 
done

Thanks!
primal

p.s. if you would like to see what i mean go to http://hal.humberc.on.ca/~crrd0120/ login name: crrd0120
 

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ECHO(3) 								 1								   ECHO(3)

echo - Output one or more strings

SYNOPSIS
void echo (string $arg1, [string $...]) DESCRIPTION
Outputs all parameters. echo is not actually a function (it is a language construct), so you are not required to use parentheses with it. echo (unlike some other language constructs) does not behave like a function, so it cannot always be used in the context of a function. Additionally, if you want to pass more than one parameter to echo, the parameters must not be enclosed within parentheses. echo also has a shortcut syntax, where you can immediately follow the opening tag with an equals sign. Prior to PHP 5.4.0, this short syn- tax only works with the short_open_tag configuration setting enabled. I have <?=$foo?> foo. PARAMETERS
o $arg1 - The parameter to output. o $... - RETURN VALUES
No value is returned. EXAMPLES
Example #1 echo examples <?php echo "Hello World"; echo "This spans multiple lines. The newlines will be output as well"; echo "This spans multiple lines. The newlines will be output as well."; echo "Escaping characters is done "Like this"."; // You can use variables inside of an echo statement $foo = "foobar"; $bar = "barbaz"; echo "foo is $foo"; // foo is foobar // You can also use arrays $baz = array("value" => "foo"); echo "this is {$baz['value']} !"; // this is foo ! // Using single quotes will print the variable name, not the value echo 'foo is $foo'; // foo is $foo // If you are not using any other characters, you can just echo variables echo $foo; // foobar echo $foo,$bar; // foobarbarbaz // Some people prefer passing multiple parameters to echo over concatenation. echo 'This ', 'string ', 'was ', 'made ', 'with multiple parameters.', chr(10); echo 'This ' . 'string ' . 'was ' . 'made ' . 'with concatenation.' . " "; echo <<<END This uses the "here document" syntax to output multiple lines with $variable interpolation. Note that the here document terminator must appear on a line with just a semicolon. no extra whitespace! END; // Because echo does not behave like a function, the following code is invalid. ($some_var) ? echo 'true' : echo 'false'; // However, the following examples will work: ($some_var) ? print 'true' : print 'false'; // print is also a construct, but // it behaves like a function, so // it may be used in this context. echo $some_var ? 'true': 'false'; // changing the statement around ?> NOTES
Note Because this is a language construct and not a function, it cannot be called using variable functions. SEE ALSO
print(3), printf(3), flush(3), Heredoc syntax. PHP Documentation Group ECHO(3)
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