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1. UNIX for Beginners Questions & Answers
Hello Team,
Any help would be much appreciated for the below scenario:
I have a sed command below where I am trying to replace the contents of 'old_pkey' variable with 'new_pkey' variable in a Soap request file (delete_request.txt). This works fine for regular string values, but this new_pkey... (8 Replies)
Discussion started by: ChicagoBlues
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2. Shell Programming and Scripting
{"name":"alR_pl-ENVIRONMENT_192_168_211_123_sDK_PROVISION_7","description":"aLR_pl-ENVIRONMENT_192_168_211_123_sDK_PROVISION_7","json_class":"Chef::Role","default_attributes":{},"override_attributes":{"yoapp":{"jboss":"5.1.0","port":"2243","warname":"soap","datacenter":"alR","ip":"192.168.211.123","... (3 Replies)
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3. Shell Programming and Scripting
Hi,
I have a string wherein i need to replace special characters with backslash and that character.
Ex:
If my string is a=qwerty123@!,
then the new string should be a_new=qwerty123\@\!\,
Thanks (3 Replies)
Discussion started by: temp_user
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4. Shell Programming and Scripting
Hi Unix Guru,
I have an requirement for replace some specail characters in a file, my file came from mainframe.
please see below example:
when open it with vi
17896660|89059215|04/24/1998 00:00:00.000000| abc 123-453-1312^M<85>^M<85>|124557
if I run cat -v I got following:... (25 Replies)
Discussion started by: ken002
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5. Shell Programming and Scripting
i need to replace the any special characters with escape characters like below.
test!=123-> test\!\=123
!@#$%^&*()-= to be replaced by
\!\@\#\$\%\^\&\*\(\)\-\= (8 Replies)
Discussion started by: laknar
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6. Shell Programming and Scripting
I have a line ending with special character and 0
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in VI mode the file will look like below, but while cat the special character wont display
i know the hexa code for the special character ^_ is \x1f and ascii code is
\0037,
... (0 Replies)
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7. Solaris
Hi ,
I want to replace the special characters in the file.
For eg: cat abc
1234/4455/acb
234/k/lll/
234`fs`fd
I want to replace / and ` with the letter a and the output should like below. How to achieve this.
1234a4455aacb
234akallla
234afsafd (2 Replies)
Discussion started by: rogerben
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8. Shell Programming and Scripting
Hi everyone
I have file1 contains:
'7832'
' 8765
6543
I want a sed command that will format as:
'7832' , '8765' , '6543'
I tried
sed -e s/\'//g -e 's/^*//;s/*$//' file1 > file2
sed -e :a -e '$!N; s/\n/ /; ta' file2
which gives: 7832 8765 6543
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9. UNIX for Dummies Questions & Answers
HI All
I need a shell script ehich removes all special characters from file and converts the file to UTF-* format
Specail characters to be removed must be configurable.
strIllegal = @"?/><,:;""'{|\\+=-)(*&^%$#@!~`";
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10. UNIX for Dummies Questions & Answers
Hi,
I have a data like this in a file,
402003279034002000100147626030003300010000000000002000029000000 ær^M^\MÍW^H
I need to replace those special char to some other char like # or $
Is there any ways to do it...
I tried commands tr,sed and many but it was not able to replace because... (1 Reply)
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bup-margin(1) General Commands Manual bup-margin(1)
NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS
--predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO
bup-midx(1), bup-save(1)
BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown- bup-margin(1)
