While ...loop

redologger · #1 01-07-2013

Code:

#!/usr/bin/ksh

totalInstance=3
c=1
SID=SID
SID_1=BOYISH
SID_2=EAGALE
SID_3=PLUNE

while [ c -le $totalInstance ]
do
    BDUMP_DIR="${SID}_${c}"
    echo "$BDUMP_DIR"

    c=`expr $c + 1`
    echo "$c"
done

Scott · #2 01-07-2013

c is a variable, you need a $ before it.

Code:

while [ "$c" -le ....
 ...
  c=$((c + 1))
...
done

rangarasan · #3 01-07-2013

Hey,

try this,

Code:

..
while [ $c ...
..

redologger · #4 01-07-2013

Quote:

Originally Posted by Scott

c is a variable, you need a $ before it.

Code:

while [ "$c" -le ....
 ...
  c=$((c + 1))
...
done

erm..i made the changes u recomanded still not able to get the value assign to SID_1 , SID_2 , SID_3

Scott · #5 01-07-2013

Code:

while [ $c -le $totalInstance ]
do
  BDUMP_DIR="${SID}_${c}"
  eval echo "\$$BDUMP_DIR"
  c=$((c + 1))
  echo "$c"
done

RudiC · #6 01-07-2013

You need either sth corresponding to bash indirection (don't know in ksh - ${!vname}?) or use eval to assign to BDUMP_DIR.

redologger · #7 01-08-2013

what happen if is:

Code:

BDUMP_DIR=/home/John/admin/"${SID}_${c}"/bdump

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The Following User Says Thank You to Scott For This Useful Post:
redologger (01-07-2013)