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Shell Programming and Scripting

Simple addition, help.

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# 1  
Old 09-23-2008
Simple addition, help.
I add up the number of args that are not blank. It works, but the printout is a string that just keep concatenating on +1. So Ex. it goes through input of: bob toto " " tom ...I get 0+1+1+1, when all I want is 3. Any help is appreciated.

Code:
count=0

for name in $*
do

  if [ "$name" != "" ]; then
  count="$count+1"
  fi

done

echo $count

# 2  
Old 09-23-2008
Some possibilities:

Code:
let count=count+1

let "count+=1"

let "count++"

Regards
# 3  
Old 09-23-2008
Might be better to test for a zero length string instead of comparing it to a blank one...
Code:
let count=0

for i in $*
do
   if [ ! -z "$name" ]; then
      let count+=1
   fi
done

echo $count

# 4  
Old 09-23-2008
If you're in ksh or bash, you can add stuff using $(( )) operator:

i=1
echo $(( $i + 1 ))

Nice thing with this construction is that you can nest the math:

a=1
b=10
echo $(( $a + $(( $b + 1 )) ))

/fimblo
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