I add up the number of args that are not blank. It works, but the printout is a string that just keep concatenating on +1. So Ex. it goes through input of: bob toto " " tom ...I get 0+1+1+1, when all I want is 3. Any help is appreciated.
Hello Seniors!!! I am trying to add to lines on a file which is delimited by character "|".
input.txt
Desired Output file should give simple addition.
output.txt
Can some one provide me simple awk solution to this. M struggling to solve this using awk & for loop inside awk.
Thanks... (2 Replies)
Hi all,
I am getting following output by using commands like sort, uniq and awk to the standard output.
110 d
40 a
59 c
9 b
3 e
Now at the end I would like to add all the numbers in column 1 and display the count of all numbers i.e. (110 + 40 + 59 + 9 + 3).
Also the output may... (3 Replies)
Hi all,
I am very new to shell programming and trying to learn out the basics.
I tried this:
$ echo `expr 20 + 30`
and it worked. But when i tried this,it does not work.
$ a=20
$ b=30
$ echo `expr a + b`
The error is:
expr: non-numeric argument
I cant understand why its... (3 Replies)
Hi I need to do the following substitution
I have to look for line starting with ABC and add 4 ":" before the first occurence of "+"in that line
Input
ABC:12:Lambert:C278472:1357:0:0:0:0:2:N::::N:9045123:NAP::+DEF
output
ABC:12:Lambert:C278472:1357.00:0.00:0:0:0:2:N::::N:9045123:NAP::::::+DEF... (5 Replies)
i need shell script to add to numbers
#!/usr/bin/sh
a=1310601600 ------> epcho time of Thu, 14 Jul 2011 00:00:00 UTC
b=864000 -------> 10 days in sec
c=`expr $a+$b`
echo $c----1311465600> this output i will use this value to delete the data from MySQL db
next i need to set... (3 Replies)
a=10.00
pattern=-11.00
b=`echo "$a $pattern" | awk ' printf("%d\n", $1 + $2)'`
echo $b
not working, also trined bc ,dc but thats not on my m/c.
also expr not supporting.
any clue? (6 Replies)
by the script, two files Q1 and Q2 will be generated on the system. Q1 will contain an integer number and Q2 also contain an integer number. i would like to add those numbers and put into new file.
excerpt from my script
22 subcount=`echo $dir/Q$qid.txt` + `echo $dir/Q$qid.txt`
23 echo... (1 Reply)
Hi
I have a file whose contents are as follows:
sorce1 LEN assumption 695 3570 0.770047 - . ID=f000001.1;source_id=A.off_LEN_10008424;
sorce1 LEN descriptive 3334 3570 . - 0 Parent=f000001.1;
sorce1 LEN ... (8 Replies)
Discussion started by: sa@@
8 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)