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Old 11-08-2006
awk question

Hello Guru's,

I have a report that prints lines with either 8 columns wide.
The last column #8 for the most part have a three character value.
My requirement is to print the whole record where the last columns value is exactly 3 characters wide and if it does not equal "AAA" or "BBB" or "CCC"

So far this is what I have
Code:
awk '{if (length($8) < 4) print $0}' 20061106_auditlog

gets me all records that have exactly 3 character wide value for column 8.
question is how do I filter within awk for certain types of values that are not "AAA" or "BBB" or "CCC".

Thanks for the help
Jerardfjay
 
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PR(1)							      General Commands Manual							     PR(1)

NAME
pr - print file SYNOPSIS
pr [ option ... ] [ file ... ] DESCRIPTION
Pr produces a printed listing of one or more files on its standard output. The output is separated into pages headed by a date, the name of the file or a specified header, and the page number. With no file arguments, pr prints its standard input. Options apply to all following files but may be reset between files: -n Produce n-column output. +n Begin printing with page n. -b Balance columns on last page, in case of multi-column output. -d Double space. -en Set the tab stops for input text every n spaces. -h Take the next argument as a page header (file by default). -in Replace sequences of blanks in the output by tabs, using tab stops set every n spaces. -f Use formfeeds to separate pages. -ln Take the length of the page to be n lines instead of the default 66. -m Print all files simultaneously, each in one column. -n Number the lines of each file. -on Offset the left margin n character positions. -sc Separate columns by the single character c instead of aligning them with white space. A missing c is taken to be a tab. -t Do not print the 5-line header or the 5-line trailer normally supplied for each page. -wn For multi-column output, take the width of the page to be n characters instead of the default 72. SOURCE
/sys/src/cmd/pr.c SEE ALSO
cat(1), lp(1) PR(1)