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Can't find string terminator "`" anywhere before EOF

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# 1  
Old 10-07-2014
Can't find string terminator "`" anywhere before EOF
// AIX 6.1

What I am trying to accomplish is to display the user name and the last login date and time in one line:

Code:
for usrlist in $(cat  alluser.txt)
do
$usrlist 
perl -e 'print scalar localtime `lsuser -a time_last_login $usrlist | awk -F '=' '{print $2}'`' 
done

However, it seems this line (tested with jdoe user account)
Code:
perl -e 'print scalar localtime `lsuser -a time_last_login jdoe | awk -F '=' '{print $2}'`'

returns an error saying
Code:
Can't find string terminator "`" anywhere before EOF

.

Can you please let me know how to resolve this error and display the user name and the converted time_last_login next each on one row?

Appreciate it!
Last edited by vbe; 10-07-2014 at 04:49 PM..
# 2  
Old 10-07-2014
Hi,
Your problem is with mutiple quote ('),so:
Code:
perl -e "print scalar localtime \`lsuser -a time_last_login jdoe | awk -F '=' '{print $2}'\`"

should work...

Regards.
# 3  
Old 10-07-2014
Quote:
Originally Posted by disedorgue
Hi,
Your problem is with mutiple quote ('),so:
Code:
perl -e "print scalar localtime \`lsuser -a time_last_login jdoe | awk -F '=' '{print $2}'\`"

should work...

Regards.
Thank you!! Is it possible that we can display the username and time on one row so that I can have a better output?

right now, I am getting like:

HTML Code:
Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31 19:00:00 1969Wed Dec 31
# 4  
Old 10-07-2014
Perl does not require the help of awk, what's the output of lsuser -a time_last_login jdoe?
# 5  
Old 10-07-2014
Quote:
Originally Posted by Aia
Perl does not require the help of awk, what's the output of lsuser -a time_last_login jdoe?
It shows:
HTML Code:
jdoe time_last_login=1412251621
What I want is as the output is:

HTML Code:
jdoe  Wed Dec 31 19:00:00 
.....
or even better

HTML Code:
jdoe   12/31/2013 19:00:00
....
Please advise.
# 6  
Old 10-07-2014
As "Aia" noted you can do all your processing in perl instead of mixing shell / perl / awk into a single code snippet...
# 7  
Old 10-07-2014
I would do it in two statements
Code:
last=`lsuser -a time_last_login jdoe | awk -F '=' '{print $2}'`
perl -le "print scalar localtime $last"
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