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Can't find string terminator "`" anywhere before EOF

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Top Forums Shell Programming and Scripting Can't find string terminator "`" anywhere before EOF
# 8  
Old 10-07-2014
We can use an awkish approach:
Code:
lsuser -a time_last_login jdoe | perl -lnaF'[\s=]' -e 'print "$F[0] ", scalar localtime($F[2])'
jdoe Thu Oct  2 06:07:01 2014

We can use another approach:
Code:
lsuser -a time_last_login jdoe | perl -ln -e '/^(\w+)\s\w+=(\d+)/ and print "$1 ", scalar localtime($2);'
jdoe Thu Oct  2 06:07:01 2014

To have your ultimate output format, we need to do some more work with the return from localtime:

Code:
lsuser -a time_last_login jdoe | perl -ln -e '/^(\w+)\s\w+=(\d+)/ and
($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst) = localtime($2) and printf("%s %02d/%02d/%d %02d:%02d:%02d\n", $1, $mon, $mday, $year+1900, $hour, $min, $sec);'
jdoe 09/02/2014 06:07:01

Last edited by Aia; 10-07-2014 at 08:40 PM.. Reason: grammar correction
# 9  
Old 10-08-2014
perldoc is a resource to help coding in perl
localtime - perldoc.perl.org

localtime takes a number of epoch seconds - what you have - and returns what in C is called a struct tm - broken down time/dates.

Read the whole page - there is not much to it. It also shows a strftime example.

strftime turns those broken down time/dates into any format of output you want. It uses the exact same time formatting as does your UNIX date command.
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