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Cut parameterized command

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# 1  
Old 07-25-2013
Cut parameterized command
Hi,

I have a cut command and i want to make it parameterized.

e.g
Code:
cut -f1-$some_value -d"/" $file_path

so in above e.g
$some_value could be a number.
$file_path is a path to a file.

But I am not able to execute the above.
The $file_path actually opens the file .....I want it to be just some path e.g /a/b/c/ and cut fields from 1-$some_value

How can this be achieved ?
Last edited by Scott; 07-25-2013 at 02:54 PM.. Reason: Code tags
# 2  
Old 07-25-2013
Code:
VAR=$(echo "$string" | cut -f$whatever)

But depending on what your shell is, there may be far better ways to do this using shell builtins. In bash for instance:

Code:
OLDIFS="$IFS" ; IFS="/"
        ARR=( $string )
IFS="$OLDIFS"

# Any contents you want from the string are available in ${ARR[0]} to however many you have.

# 3  
Old 07-25-2013
mine is ksh.but what you have suggested wont help me....how do I parametrize it ?
# 4  
Old 07-25-2013
In ksh, you would do:

Code:
OLDIFS="$IFS" ; IFS="/"
        set -a ARR $string
IFS="$OLDIFS"

...then use the array the same way as in bash.
This User Gave Thanks to Corona688 For This Post:
vital_parsley
# 5  
Old 07-25-2013
Quote:
Originally Posted by vital_parsley
how do I parametrize it ?
Code:
${ARR[$N]}

# 6  
Old 07-25-2013
isnt there a simpler way to execute the cut commands with the way I have asked..
I am trying to get the directory of the file using the cut command.
I am not master with unix commands so looking for a simpler command ? Smilie
# 7  
Old 07-25-2013
Read my posts again, the 'simple' way is the very first thing I posted. For a quick-fix or something you only do once, it will do.

If you call it in a loop more than once, you will find it is extremely slow and may want to try one of the other options.
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