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1. Shell Programming and Scripting
I used the below script to Sum up a field in a file based on some unique values. But the problem is when it is summing up the units, it is truncating to 2 decimals and not 6 decimals as in the input file (Input file has the units with up to 6 Decimals – Sample data below, when the units in the 2... (4 Replies)
Discussion started by: brlsubbu
4 Replies
2. UNIX for Dummies Questions & Answers
How to round off a decimal number to higher whole number using ceil command in unix?
Eg. 4.41 or 4.11 or 4.51 should be rounded off to 5. (11 Replies)
Discussion started by: SanjayKumar28
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3. Shell Programming and Scripting
Hi,
I wanted to round all the values in a column to nearest integer. I have multiple files with only two columns and I want to round values in column 2. e.g
input_file
A1 23.971578 A2 34.624976 A3 46.403446 A4 375 A5 1 A6 3 A7 ... (3 Replies)
Discussion started by: ashu0001
3 Replies
4. Shell Programming and Scripting
Hi Friends,
This is my last post for today.
My input file is
chr1 100 200
chr1 123 300
chr1 300 400
chr1 420 520
chr10 132344343 132348674
When I try using this command
awk '{v=($3+$2)/2; print $0"\t"v}' 1
This is my output
chr1 100 200 150
chr1 123 300 211.5 (2 Replies)
Discussion started by: jacobs.smith
2 Replies
5. Shell Programming and Scripting
I am trying to perform arithmetric, for example, to increment the value of variable $a (say 3) by 0.05 but when I tried the following expression
let a=a+0.05
or a=$((a+0.05))
both returned
3.0499999999999998
I want to keep 2 decimal places so it returns 3.05 instead. (6 Replies)
Discussion started by: piynik
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6. Shell Programming and Scripting
i need to multiplay a number with 1.00.. so that the output should contain two decimal places at end..
for example...
236 * 1.00 = 236.00
245.8 * 1.00 = 245.80
but when i perform multiplication it shows output as.
236
245.8
can anyone help me to get the actual output of... (11 Replies)
Discussion started by: arunmanas
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7. Shell Programming and Scripting
i have a script in which awk prints "($2-1700)/10000"
and the answer is -0.07,but i want the answer in 4 decimal places.
that is -0.0700.
How can i sue awk to get my results in four decimal places (4 Replies)
Discussion started by: tomjones
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8. UNIX for Dummies Questions & Answers
Hi,
I am currently using tcsh
I am trying to round a decimal number to the ten-thousandths place
For instance:
1.23456 is rounded up towards 1.2346
I am not looking for truncation, but for rounding. Anyone know how to do this with awk or expr?
Thanks (2 Replies)
Discussion started by: miniwheats
2 Replies
9. Shell Programming and Scripting
I have a perl script that reports the avg time of a application call and the total number of calls. This works fine, however I would like to trim the number of decimal places reported from 12 to like 3 and I don't know how.
Any suggestions? Here is what I use to get the avg time...
for $eRef (... (2 Replies)
Discussion started by: theninja
2 Replies
bup-margin(1) General Commands Manual bup-margin(1)
NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS
--predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO
bup-midx(1), bup-save(1)
BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown- bup-margin(1)