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calculate size of some files

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# 1  
Old 07-21-2005
calculate size of some files
Hi,
1-I want to calculate the size of all files which are generated during last month in a directory. How can I do that ?
Of cours, I find them by :
$ls -l | grep jun
but how to calculate the sum of their size ?
2- the same but for all files generated last month and before that.
many thanks before.
# 2  
Old 07-21-2005
If you combine the following scripts you should get what you want:

http://www.pixelbeat.org/scripts/find_mm_yyyy
http://www.pixelbeat.org/scripts/add

The following might work straight off?

find_mm_yyyy 06 2005 -printf "%s\n" | add
# 3  
Old 07-21-2005
thank you.
I want to find all from may 2005
For the first I have this problem :
$altest
Usage: altest MM YYYY
$altest 05 2005
date: illegal option -- -
date: illegal option -- t
date: illegal option -- c

How should I enter the date then ?
Thanks.
# 4  
Old 07-21-2005
Code:
ls -ltr | grep "Jun" | awk -F" " 'BEGIN { sum=0 } { sum+=$5 }END { print sum }'

Code:
ls -ltr | grep -v "Jul" | awk -F" " 'BEGIN { sum=0 } { sum+=$5 }END { print sum }'


Note : You may have to take care of 'year' part in the grep.
Just tune this based on your needs.
# 5  
Old 07-21-2005
Quote:
Originally Posted by big123456
thank you.
I want to find all from may 2005
For the first I have this problem :
$altest
Usage: altest MM YYYY
$altest 05 2005
date: illegal option -- -
date: illegal option -- t
date: illegal option -- c

How should I enter the date then ?
Thanks.
the problem is that the script is using GNU-specific 'date' options. If you don't have GNU 'date' - you're out of luck with this script.

This is not bullet-proof, but.... [Solaris 9 stock 'ls']
Code:
ls -lrt | nawk '$6 == "Jun" {sum+=$5} END{print sum}'

If you need a better solution, you would need to use 'find' with '-newer' options. You might wanna search FAQs for more leads/options.
Last edited by vgersh99; 07-21-2005 at 01:03 PM..
# 6  
Old 07-21-2005
Code:
sum=0 
for filesize in  $(  ls -la |grep $(date -d '1 month ago' +%Y-%m )|awk '{print $5}'  ) 
do 
   let sum=sum+filesize 
done 
echo sum $sum

# 7  
Old 07-21-2005
Quote:
Originally Posted by becket
Code:
sum=0 
for filesize in  $(  ls -la |grep $(date -d '1 month ago' +%Y-%m )|awk '{print $5}'  ) 
do 
   let sum=sum+filesize 
done 
echo sum $sum

Again - this is GNU-based AND you're using grep AND awk all in one - in most cases it's considered UUOG
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