calculate size of some files


 
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# 8  
Old 07-21-2005
Quote:
Originally Posted by bhargav
Code:
ls -ltr | grep "Jun" | awk -F" " 'BEGIN { sum=0 } { sum+=$5 }END { print sum }'

...
Hi, I'm Henrik and I am a new member here!

The above is funny: in one of my current projects, I also needed to get the size
of a file and I also cut out the fifth element of 'ls'. Is that really portable? Is the
output of ls always such that the fifth element is the size? I checked on many systems
and it was, but you never know.

BTW, this is my project:

http://www.theiling.de/projects/bar.html

An ASCII/Console/Command line progress bar written in pure Bourne shell
mainly (or better, initially) for portable install scripts.
# 9  
Old 07-22-2005
thank you. but it gives me :
date: illegal option -- d
usage: date [-u] mmddHHMM[[cc]yy][.SS]
date [-u] [+format]
date -a [-]sss[.fff]
Any way how can I format date to have just last month ? Thank you.
# 10  
Old 07-22-2005
Many thanks.
# 11  
Old 07-22-2005
this is great, now...

Quote:
Originally Posted by bhargav
Code:
ls -ltr | grep "Jun" | awk -F" " 'BEGIN { sum=0 } { sum+=$5 }END { print sum }'

Code:
ls -ltr | grep -v "Jul" | awk -F" " 'BEGIN { sum=0 } { sum+=$5 }END { print sum }'


Note : You may have to take care of 'year' part in the grep.
Just tune this based on your needs.
now for the next question on this same note...
If you have unknown directory names within a master directory, that you wish to have an output like the following...

1: directory name
2: sum of contents of file sizes in directory and subs in bytes
and go to next to provide a list, all within the same starting point...
How would the script line look?

This is just derived from modifying your script in substituting the Jun for a known directory name.

??
# 12  
Old 07-22-2005
Error

Again, not bullet-proof [stock Solaris' 9 "find"], but......

find topDirectory -type f -ls | nawk -v month='Jun' -f files.awk

files.awk:
Code:
BEGIN {
  FSpath="/"
}

$8 == month {
    n=split($NF, pathA, FSpath)
    for(i=1; i < n; i++) {
       p = ( i == 1) ? pathA[i] : p FSpath pathA[i]
       arr[p] += $7
    }
    split("", pathA)
}
END {
  for( i in arr)
     printf("[%s] -> [%d]\n", i, arr[i])
}

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