Conditional replacements


 
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Old 04-26-2011
Conditional replacements

Hi,
I have a requirement as below
Input
Code:
  Jacuzzi,"Jet Rings, Pillows",Accessory,Optional,,9230917,69094,,P556805,69094,FALSE,1,0,,
  Jacuzzi,"Jet Rings, Pillows, Skirt/Apron",Accessory,Optional,,9230917,69094,,P556805,69094,FALSE,1,0,,


Output
Code:
  Jacuzzi,"Jet Rings!@% Pillows",Accessory,Optional,,9230917,69094,,P556805,69094,FALSE,1,0,,
  jacuzzi,"Jet Rings!@% Pillows!@% Skirt/Apron",Accessory,Optional,,9230917,69094,,P556805,69094,FALSE,1,0,,


i.e. commas present within the column which has double quotes has to be replaced by the !@%.


To achieve this I have used sed.
Code:
sed -e 's/\("[^"][^,]*\),\([^"]*\),\(
[^"]*[^,]"\)/\1!@%\2!@%\3/g' -e 's/\("[^"][^,]*\),\([^"]*[^,]"\)/\1!@%\2/g' "$file"



But now the requirement has changed. Previously I was expecting only 1 or 2 commas i.e. a pattern like "abc,gbf" or "abc,kil,jik" can only come but now I have to generalize it for any no of commas i.e 1,2,3 ---



Any ideas about how to achieve the above.


Thanks for your help in advance.

Last edited by Franklin52; 04-27-2011 at 04:09 AM.. Reason: Please use code tags
 
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