Need to take one part from a string


 
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# 1  
Old 03-09-2011
Error Need to take one part from a string

I have a string something like "/opt/src/default.cfg" OR /opt/src/common/one

This whole string stored in an array. The problem is this string is not constant and it will keep on changing as lot of strings are stored in the array and it will be look like :-
case 1
/opt/src/default.cfg
/opt/sys/sec/default.cfg
/opt/st95psd.cfg

Sometimes it will be like

case2

/opt/src/common/one
/opt/src/common/two

only thing repeating is ".cfg" part or "/opt/src/common" .From case 1, I want only the last part which contain ".cfg" It means "default.cfg" or "st95psd.cfg" in this case. From case2, I want string which is comming after "/opt/src/common"

Please help me out

Thanks in advance
Renjesh Raju

Last edited by Renjesh; 03-09-2011 at 08:58 AM..
# 2  
Old 03-09-2011
Array defined in what language?
# 3  
Old 03-09-2011
In shell scripting
# 4  
Old 03-09-2011
use:
Code:
basename "${string}"

# 5  
Old 03-09-2011
have a look at the basename utility. By defualt it will strip off anything that looks like a path so
Code:
for fn in \
/opt/src/default.cfg \
/opt/sys/sec/default.cfg \
/opt/st95psd.cfg \
/opt/src/common/one \
/opt/src/common/two; do basename $fn; done

(you may have to put all that on one line)
this should output
Code:
default.cfg
default.cfg
st95psd.cfg
one
two

# 6  
Old 03-09-2011
I will clarify a little more with an example

I have two strings ..

/opt/src/deafult.cfg and /opt/src/esr/common/test1

From this i want only "default.cfg" and "test1" ...

Note :- it is not always "/opt/src/default.cfg" sometimes it will be "/opt/src/esr/default.cfg" like this. ".cfg" will be repeating always.

Other case, "/opt/src/esr/common" will repeat always, but i want only "test1" from that ..

Please help me ...
# 7  
Old 03-09-2011
As said:
Code:
# basename /opt/src/deafult.cfg
deafult.cfg
# basename  /opt/src/esr/common/test1
test1

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