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Sort two columns in a field, one of them being a date

 
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Old 07-28-2009
Sort two columns in a field, one of them being a date
Hi,

I have a set of columns in a csv file, my first row being an integer and 2nd being a date. I want to first sort it using the first column and then by the second.

for e.g. i have ,

1234,09/05/2009,hi
5678,01/01/2008,hi
1234,11/03/2006,hello
5678,28/07/2010,hello

i tried this but wont work because the separator is "," :::

sort -t "," -k1 -k2.7,2.10 -k2.4,2.5M -k2.1,2.2 test.csv > hi.csv

Thanks in advance,
SD
 
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ibase_fetch_assoc

IBASE_FETCH_ASSOC(3)							 1						      IBASE_FETCH_ASSOC(3)

ibase_fetch_assoc - Fetch a result row from a query as an associative array

SYNOPSIS

       array ibase_fetch_assoc (resource  $result, [int  $fetch_flag])

DESCRIPTION

	Fetch a result row from a query as an associative array.

       ibase_fetch_assoc(3)  fetches  one  row	of data from the $result. If two or more columns of the result have the same field names, the last
       column will take precedence. To access the other column(s) of the same name, you either need to access the result with numeric  indices	by
       using ibase_fetch_row(3) or use alias names in your query.

PARAMETERS

	      o $result
		- The result handle.

	      o $fetch_flag
		-$fetch_flag  is  a  combination  of the constants IBASE_TEXT and IBASE_UNIXTIME ORed together. Passing IBASE_TEXT will cause this
		function to return BLOB contents instead of BLOB ids. Passing IBASE_UNIXTIME will cause this function to return  date/time  values
		as Unix timestamps instead of as formatted strings.

RETURN VALUES

	Returns an associative array that corresponds to the fetched row. Subsequent calls will return the next row in the result set, or FALSE if
       there are no more rows.

SEE ALSO

       ibase_fetch_row(3), ibase_fetch_object(3).

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