Shell Programming and Scripting

Hi All,
Am copying mulitple files in a directory in names File0,File1,File2 etc.
I need to print separately the PID of these copies using File names.

Code:

for((i=0;i<5;i++))
do
mypid=`ps aux | awk '/File$i/ && !/awk/ { print $2 }'`
echo PID is $mypid
done

It printed nothing. Thinking "File$i" is not found. Am i right? Is there a way to find the PID of a process using variable substituition? If not, how it cud be achieved?

FYI,I got the PID of FIle0 or FIle1 if i use its name specifically like,

Code:

mypid=`ps aux | awk '/File0/ && !/awk/ { print $2 }'`
echo PID is $mypid

Thanks,
Amio