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1. Shell Programming and Scripting
Hello,
I have a requirement to ignore few lines in a file before keyword FILEHEADER . As soon as there is keyword FILEHEADER is identified in file , it will form another file with data from FILEHEADER to whatever in file after FILEHEADER.
I wrote
filename=$1
awk... (4 Replies)
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2. Solaris
Trying to compile a C program recievin this
hello.c:1:19: fatal error: stdio.h: No such file or directory
gcc is installed on the system.
echo $PATH
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3. Shell Programming and Scripting
Hi guys
I have two file which I sdiff.
ie
file 1: AA,12,34,56,,789,101,,6666
file 2: AA,12,34,56,,789,101,,7777
The last comma separated value will always change from one day to the next.
Is there another unix utility I can use that will sdiff two files but ignore the last comma... (1 Reply)
Discussion started by: wny201
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4. Programming
Hi All,
I am new to linux and Programming.
Inside the file stdio.h, there is a description about FILE structure. Which has many internal data members like _p, _r, _flags etc.
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5. Shell Programming and Scripting
Dear Friends,
I want to decrypt 2 different file types in a folder (ZIP files and GPG files).
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6. Shell Programming and Scripting
HI,
command to cat a readable file by ignoring the first line and last line
or command to cat a readable file by ignoring the lines with delimiter
Please advise on this. (2 Replies)
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7. Shell Programming and Scripting
Hi,
sumdays before i had posted a query with same subject.
i got sum great help from great ppl which solved my problem then.
But now there is a small problem with the code that i need the experts help upon.
for parsing a text
like this
where $ had been the delimiter between... (3 Replies)
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8. Shell Programming and Scripting
i have a file called Cleaner1.log . This files have some blank lines also.My requirement is that it should ignore the blank lines and give me the lines that contain some data.
I m using this logic in a script:
below the contents of file :
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9. UNIX for Dummies Questions & Answers
so i have a simple file called -x and i need it renamed to x
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... (5 Replies)
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10. UNIX for Dummies Questions & Answers
Hi everyone,
$ more abcdefg.ksh
abcdef
alpha beta gamma
abcdef
abcdef
lmnop
$ wc sachin1.ksh
5 7 132 abcdefg.ksh
if you see it shows that file has got 240 characters. I actually want to count how many characters... (1 Reply)
Discussion started by: sachin.gangadha
1 Replies
bup-margin(1) General Commands Manual bup-margin(1)
NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS
--predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO
bup-midx(1), bup-save(1)
BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown- bup-margin(1)