Shell Programming and Scripting

commad is like this

Code:

cat filecount.txt | awk -F " " '{print $9}'| grep rcm*200212*

the problem is with * its not taking * for grep.

grep does regular expressions, not globs. ".*" acts more like what you want -- "." means "match any single character", and * means "zero or more of the previous character". Regular expressions are also different in that they don't need to match the entire line the way globs do.

And if you're using awk, you can do it all in awk anyway.

And that's a useless use of cat.

I think this regex does what you want, but without seeing the input data I can't be positive:

Code:

awk awk -F " " '$9 ~ /^rcm.*200212/ {print $9}' filename

dear Corona688

not working

Try this:

Code:

awk -F " " '{print $9}'filecount.txt | grep "rcm*200212*"

The above post only repeats your original problem.

In what way is it "not working"? Without your original input data, I cannot test my answer against your data, and must make assumptions about what you have. I tried to reverse engineer your broken answer into what I thought you wanted, and being it was only a guess, guessed wrong.

Please post some of your original input so I don't need to guess.

Good response Corona. I was thinking the same thing.

@Corona

your awk statement has two awk

It should be one right ?

Code:

 
awk awk -F " " '$9 ~ /^rcm.*200212/ {print $9}' filename