I m trying to pass variable to sed.
export var=140920060731
sed -e '/$var/d' file
but no luch so far..? any body has any idea abt it
Is there any way to pass variable to SED?
Thanks ,
Manish (2 Replies)
Hi,
In normal shell scripting, how do you pass the output of a command to a variable, instead of a file and be able to use it later?
The code is:
#!/bin/bash
who | cut -d" " -f1 > onlineusers
Instead of passing the output of the above command to the file called 'onlineusers'... (1 Reply)
Dear All,
I want to print a file.
First I tried with this
sed '2q;d' filename
it worked. But when i put following it is not working
x=2;
sed '$xq;d' filename
Would any one suggest how to pass the variable? (7 Replies)
Hi All,
Hope someone can advise here as I have been struggling to find a syntax that works here. I have tried a stack of combination I have seed in the forums but I think because I have needed to use "" and `` in the statments another method is found.
I am reading in lines with the following... (1 Reply)
Hi,
I'm new here so I want to say hello to everyone first!
I searched google and this forum for a similar problem, but wasn't successful
#! /bin/bash
I'm trying to output (echo) n lines of a text file to the screen (later into another file).
But I have problem with the sed command, it won't... (1 Reply)
Hi,
I have a problem with passing a echo output into a variable in bash
file='1990.tar'
NAME='echo $file | cut -d '.' -f1';
echo $NAME
the result is
echo $file | cut -d . -f1
however with this one,#!/bin/bash
file='1990.tar'
echo $file | cut -d '.' -f1
the result is what I... (2 Replies)
I have a variable $WORDS that contains a string
Then i want to use sed to break it up.
echo $WORDS | sed 's// /g'
I tried setting this as a variable by doing
WORDS2=`echo $WORDS | sed 's// /g'`
But when i do this it does not return me to the prompt properly
ie.
jmpprd-v1>
jmpprd-v1>... (4 Replies)
Stumped with the formatting of the awk output when used with variables, e.g.:
awk -F, 'BEGIN {OFS=","} print {$2,$3,$4}' $infile1
produces the desired output (with rows), but when echoing the variable below, the output is one continuous line
var1=$(awk -F, 'BEGIN {OFS=","} print... (4 Replies)
Hi,
I want to pass value of a variable track_line which is the line number to sed. Sed should print the lines starting from track_line till the last
line of the file. I tried the below command but it is not working.
sed -n '${track_line},$p' latest_log_file
I tried using the below too but... (1 Reply)
I have a below syntax its working fine...
var12=$(ps -ef | grep apache | awk '{print $2,$4}')
Im getting expected output as below:
printf "%b\n" "${VAR12}"
dell 123
dell 456
dell 457
Now I wrote a while loop.. the output of VAR12 should be passed as input parameters to while loop and results... (5 Replies)
Discussion started by: sam@sam
5 Replies
LEARN ABOUT PHP
func_get_arg
FUNC_GET_ARG(3) 1 FUNC_GET_ARG(3)func_get_arg - Return an item from the argument listSYNOPSIS
mixed func_get_arg (int $arg_num)
DESCRIPTION
Gets the specified argument from a user-defined function's argument list.
This function may be used in conjunction with func_get_args(3) and func_num_args(3) to allow user-defined functions to accept variable-
length argument lists.
PARAMETERS
o $arg_num
- The argument offset. Function arguments are counted starting from zero.
RETURN VALUES
Returns the specified argument, or FALSE on error.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.0 | |
| | |
| | This function can now be used in parameter |
| | lists. |
| | |
| 5.3.0 | |
| | |
| | If this function is called from the outermost |
| | scope of a file which has been included by call- |
| | ing include(3) or require(3) from within a func- |
| | tion in the calling file, it now generates a |
| | warning and returns FALSE. |
| | |
+--------+---------------------------------------------------+
ERRORS /EXCEPTIONS
Generates a warning if called from outside of a user-defined function, or if $arg_num is greater than the number of arguments actually
passed.
EXAMPLES
Example #1
func_get_arg(3) example
<?php
function foo()
{
$numargs = func_num_args();
echo "Number of arguments: $numargs
";
if ($numargs >= 2) {
echo "Second argument is: " . func_get_arg(1) . "
";
}
}
foo(1, 2, 3);
?>
The above example will output:
Number of arguments: 3
Second argument is: 2
Example #2
func_get_arg(3) example before and after PHP 5.3
test.php
<?php
function foo() {
include './fga.inc';
}
foo('First arg', 'Second arg');
?>
fga.inc
<?php
$arg = func_get_arg(1);
var_export($arg);
?>
Output previous to PHP 5.3:
Output in PHP 5.3 and later:
Warning: func_get_arg(): Called from the global scope - no function
context in /home/torben/Desktop/code/ml/fga.inc on line 3
false
Example #3
func_get_arg(3) example of byref and byval arguments
<?php
function byVal($arg) {
echo 'As passed : ', var_export(func_get_arg(0)), PHP_EOL;
$arg = 'baz';
echo 'After change : ', var_export(func_get_arg(0)), PHP_EOL;
}
function byRef(&$arg) {
echo 'As passed : ', var_export(func_get_arg(0)), PHP_EOL;
$arg = 'baz';
echo 'After change : ', var_export(func_get_arg(0)), PHP_EOL;
}
$arg = 'bar';
byVal($arg);
byRef($arg);
?>
The above example will output:
After change : 'bar' As passed : 'bar' After change : 'baz'
NOTES
Note
Because this function depends on the current scope to determine parameter details, it cannot be used as a function parameter in ver-
sions prior to 5.3.0. If this value must be passed, the results should be assigned to a variable, and that variable should be
passed.
Note
If the arguments are passed by reference, any changes to the arguments will be reflected in the values returned by this function.
Note
This function returns a copy of the passed arguments only, and does not account for default (non-passed) arguments.
SEE ALSO
... syntax in PHP 5.6+, func_get_args(3), func_num_args(3).
PHP Documentation Group FUNC_GET_ARG(3)