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Top Forums Shell Programming and Scripting Cut command not working in for loop Post 302863753 by renuk on Tuesday 15th of October 2013 05:15:08 AM
Old 10-15-2013
hi,

i tried this command it is giving below error:
ls -ld GTDA_Dly_Sls_SS_136_20130917.20130917205418.psv
/bin/ls: cannot access GTDA_Dly_Sls_SS_136_20130917.20130917205418.psv: No such file or directory

but my path contains .xls file which contains many files in it..

/dm/RMDW_LandingZone/dev/work_area/ABaC_reregister> more file_GTDA.xls
GTDA_Dly_Pmix_AT_136_20130917.20130917205418.psv
GTDA_Dly_Pmix_AT_136_20130917.20130917205619.psv
GTDA_Dly_Pmix_AT_66_20130917.20130917205619.psv
GTDA_Dly_Pmix_CA_12_20130917.20130917205619.psv
GTDA_Dly_Sls_SS_136_20130917.20130917205418.psv

---------- Post updated at 02:45 PM ---------- Previous update was at 02:32 PM ----------

hi,

the problem is the files which i am passing to temp folder after below command ...

var1=`cat file_GTDA.xls|grep 'GTDA_Dly_Sls_'`
var4="|"
for i in $var1
do
var3=`cut -d "$var4" -f18,19 $i|sort -u`
var2=$var4""$var3
sed -n 's/'"$var2"'//p' $i> ./temp/$i
# sed -e 's/'"$var2"'//p' $i> ./temp/$i
done

excpected files are passed to temp but with 0 bytes./dm/RMDW_LandingZone/dev/work_area/ABaC_reregister/temp> ls -ltr
total 8
drwxrwxrwx 2 mc25730 dstage 4096 2013-10-15 02:59 renamed_files
-rw-rw-r-- 1 mc25730 dstage 0 2013-10-15 02:59 GTDA_Dly_Sls_SS_136_20130917.20130917205418.psv
-rw-rw-r-- 1 mc25730 dstage 0 2013-10-15 02:59 GTDA_Dly_Pmix_CA_12_20130917.20130917205619.psv
-rw-rw-r-- 1 mc25730 dstage 0 2013-10-15 02:59 GTDA_Dly_Pmix_AT_66_20130917.20130917205619.psv
-rw-rw-r-- 1 mc25730 dstage 0 2013-10-15 02:59 GTDA_Dly_Pmix_AT_136_20130917.20130917205619.psv
-rw-rw-r-- 1 mc25730 dstage 0 2013-10-15 02:59 GTDA_Dly_Pmix_AT_136_20130917.20130917205418.psv

i think problem is coming while i pass variable in cut and sed command ..
 

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DEBUG_ZVAL_DUMP(3)							 1							DEBUG_ZVAL_DUMP(3)

debug_zval_dump - Dumps a string representation of an internal zend value to output

SYNOPSIS
void debug_zval_dump (mixed $variable, [mixed $...]) DESCRIPTION
Dumps a string representation of an internal zend value to output. PARAMETERS
o $variable - The variable being evaluated. RETURN VALUES
No value is returned. EXAMPLES
Example #1 debug_zval_dump(3) example <?php $var1 = 'Hello World'; $var2 = ''; $var2 =& $var1; debug_zval_dump(&$var1); ?> The above example will output: &string(11) "Hello World" refcount(3) Note Beware the refcount The refcount value returned by this function is non-obvious in certain circumstances. For example, a developer might expect the above example to indicate a refcount of 2. The third reference is created when actually calling debug_zval_dump(3). This behavior is further compounded when a variable is not passed to debug_zval_dump(3) by reference. To illustrate, consider a slightly modified version of the above example: Example #2 <?php $var1 = 'Hello World'; $var2 = ''; $var2 =& $var1; debug_zval_dump($var1); // not passed by reference, this time ?> The above example will output: string(11) "Hello World" refcount(1) Why refcount(1)? Because a copy of $var1 is being made, when the function is called. This function becomes even more confusing when a variable with a refcount of 1 is passed (by copy/value): Example #3 <?php $var1 = 'Hello World'; debug_zval_dump($var1); ?> The above example will output: string(11) "Hello World" refcount(2) A refcount of 2, here, is extremely non-obvious. Especially considering the above examples. So what's happening? When a variable has a single reference (as did $var1 before it was used as an argument to debug_zval_dump(3)), PHP's engine opti- mizes the manner in which it is passed to a function. Internally, PHP treats $var1 like a reference (in that the refcount is increased for the scope of this function), with the caveat that if the passed reference happens to be written to, a copy is made, but only at the moment of writing. This is known as "copy on write." So, if debug_zval_dump(3) happened to write to its sole parameter (and it doesn't), then a copy would be made. Until then, the parameter remains a reference, causing the refcount to be incremented to 2 for the scope of the function call. SEE ALSO
var_dump(3), debug_backtrace(3), References Explained, References Explained (by Derick Rethans). PHP Documentation Group DEBUG_ZVAL_DUMP(3)
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