hi guys.
in bash is there any other way of limiting the time displayed to HH:MM
appart from
(date +"%H:%M") and (date +"%R")?
i want to input time into a database in the form HH:MM
have tried NOW() but this gives me HH:MM:SS
thanks in advance (1 Reply)
I have a comma delimited log file which has the date as MM/DD/YY in the 2nd column, and HH:MM:SS in the 3rd column.
I need to change the date format to YYYY-MM-DD and merge it with the the time HH:MM:SS. How will I got about this?
Sample input
02/27/09,23:52:31
02/27/09,23:52:52... (3 Replies)
I have a list of dates in the following format: mm/dd/yyyy and want to change these to the MySQL standard format: yyyy-mm-dd.
The dates in the original file may or may not be zero padded, so April is sometimes "04" and other times simply "4".
This is what I use to change the format:
sed -i '' -e... (2 Replies)
I need to increment a date value through shell script.
Input value consist of start date and end date in DATE format of unix.
For eg.
I need increment a date value of 1/1/09 to 31/12/09 i.e for a whole yr.
The output must look like
1/1/09
2/2/09
.
.
.
31/1/09
.
.
1/2/09
.
28/2/09... (1 Reply)
Could anyone suggest me on how to write unix script for displaying yesterdays date ie. if today is 2nd Mar then when i run .sh script i should get displayed as "01-Mar-2010". (5 Replies)
Hi Experts
I'm struggling with the dates in bash scripting.
here is my code
due1=`grep "$member" Due.txt | tail -n 1 | cut -d "," -f2 | tr -d "\15"`
duedate1=`date +%Y-%m-%$due1`
echo $due1
echo $duedate1
if I execute the above code
I get output as
10
2013-09 %10
... (2 Replies)
Hi Unix Gurus,
I would like to rename several files in a Unix Directory . The filenames can have more than 1 underscore ( _ ) and the last underscore is always followed by a date in the format mmddyyyy. The Extension of the files can be .txt or .pdf or .xls etc and is case insensitive ie... (1 Reply)
I have a script below and wanted to change the output into three different file format (3 separate script)
#!bin/bash
#input file format postwrf_d01_20131206_0600_f08400.grb2
#postwrf_d01_YYYYMMDD_ZZZZ_f0HHHH.grb2
#zzzz= 0000,0600,1200,1800 (in UTC)
#HHHH=00000,00600,01200,01800 ..ect (in... (1 Reply)
I'm trying to change date format using this script from day/month/year to month/day/year
#!/bin/bash
while read line; do
echo "$line"
date=$(echo "$line" | cut -d/ -f1 )
month=$(echo "$line" | cut -d/ -f2 )
echo $month"/"$date"/2017"
done < ~/Downloads/Dates.csv
But I get output as... (5 Replies)
Discussion started by: sharat
5 Replies
LEARN ABOUT DEBIAN
hdate_struct
hdate_struct(3) libhdate C language hdate_struct(3)NAME
hdate_struct -
libhdate Hebrew date struct
SYNOPSIS
#include <hdate.h>
Data Fields
int hd_day
int hd_mon
int hd_year
int gd_day
int gd_mon
int gd_year
int hd_dw
int hd_size_of_year
int hd_new_year_dw
int hd_year_type
int hd_jd
int hd_days
int hd_weeks
Detailed Description
libhdate Hebrew date struct
Field Documentation
int hdate_struct::hd_day The number of day in the hebrew month (1..31).
int hdate_struct::hd_mon The number of the hebrew month 1..14 (1 - tishre, 13 - adar 1, 14 - adar 2).
int hdate_struct::hd_year The number of the hebrew year.
int hdate_struct::gd_day The number of the day in the month. (1..31)
int hdate_struct::gd_mon The number of the month 1..12 (1 - jan).
int hdate_struct::gd_year The number of the year.
int hdate_struct::hd_dw The day of the week 1..7 (1 - sunday).
int hdate_struct::hd_size_of_year The length of the year in days.
int hdate_struct::hd_new_year_dw The week day of Hebrew new year.
int hdate_struct::hd_year_type The number type of year.
int hdate_struct::hd_jd The Julian day number
int hdate_struct::hd_days The number of days passed since 1 tishrey
int hdate_struct::hd_weeks The number of weeks passed since 1 tishrey
Author
Generated automatically by Doxygen for libhdate C language from the source code.
Version 1.4 Sun Jan 8 2012 hdate_struct(3)