09-02-2013
Date format in Bash Script
Hi Experts,
We get "Day" of a month in a variable, so how to make date of out it?
To make more sense
if my variable $DAY contains "12" and month and year will be current date (as of today)
so I want to see as output as 2013-09-12.
How can I achive this bash script??
Any help is highly appreciated.
Thank you
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IDATE(3) 1 IDATE(3)
idate - Format a local time/date as integer
SYNOPSIS
int idate (string $format, [int $timestamp = time()])
DESCRIPTION
Returns a number formatted according to the given format string using the given integer $timestamp or the current local time if no time-
stamp is given. In other words, $timestamp is optional and defaults to the value of time(3).
Unlike the function date(3), idate(3) accepts just one char in the $format parameter.
PARAMETERS
o $format
-
The following characters are recognized in the $format parameter string
+------------------+---------------------------------------------------+
|$format character | |
| | |
| | Description |
| | |
+------------------+---------------------------------------------------+
| | |
| B | |
| | |
| | Swatch Beat/Internet Time |
| | |
| | |
| d | |
| | |
| | Day of the month |
| | |
| | |
| h | |
| | |
| | Hour (12 hour format) |
| | |
| | |
| H | |
| | |
| | Hour (24 hour format) |
| | |
| | |
| i | |
| | |
| | Minutes |
| | |
| | |
| I (uppercase i) | |
| | |
| | returns 1 if DST is activated, 0 otherwise |
| | |
| | |
| L (uppercase l) | |
| | |
| | returns 1 for leap year, 0 otherwise |
| | |
| | |
| m | |
| | |
| | Month number |
| | |
| | |
| s | |
| | |
| | Seconds |
| | |
| | |
| t | |
| | |
| | Days in current month |
| | |
| | |
| U | |
| | |
| | Seconds since the Unix Epoch - January 1 1970 |
| | 00:00:00 UTC - this is the same as time(3) |
| | |
| | |
| w | |
| | |
| | Day of the week ( 0 on Sunday) |
| | |
| | |
| W | |
| | |
| | ISO-8601 week number of year, weeks starting on |
| | Monday |
| | |
| | |
| y | |
| | |
| | Year (1 or 2 digits - check note below) |
| | |
| | |
| Y | |
| | |
| | Year (4 digits) |
| | |
| | |
| z | |
| | |
| | Day of the year |
| | |
| | |
| Z | |
| | |
| | Timezone offset in seconds |
| | |
+------------------+---------------------------------------------------+
o $timestamp
- The optional $timestamp parameter is an integer Unix timestamp that defaults to the current local time if a $timestamp is not
given. In other words, it defaults to the value of time(3).
RETURN VALUES
Returns an integer.
As idate(3) always returns an integer and as they can't start with a "0", idate(3) may return fewer digits than you would expect. See the
example below.
ERRORS
/EXCEPTIONS
Every call to a date/time function will generate a E_NOTICE if the time zone is not valid, and/or a E_STRICT or E_WARNING message if using
the system settings or the $TZ environment variable. See also date_default_timezone_set(3)
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.1.0 | |
| | |
| | Now issues the E_STRICT and E_NOTICE time zone |
| | errors. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
idate(3) example
<?php
$timestamp = strtotime('1st January 2004'); //1072915200
// this prints the year in a two digit format
// however, as this would start with a "0", it
// only prints "4"
echo idate('y', $timestamp);
?>
SEE ALSO
date(3), getdate(3), time(3).
PHP Documentation Group IDATE(3)