Finding the modified timestamp of files from the piped output of du command
Version Info
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RHEL 5.4
Since ls command lists file sizes in Bytes which can be long I use du command like below.
I have run the du command for the below files as shown below.
But I want pipe this output to ls command just to see the modified timestamp for these files.
How can I do this ?
Last week I was using the command:
' find /directory -mtime -2 -print' and it showed all the files modified within that period. However, now it only displays the directories and not the files modified. The only thing that changed is that I was granted access to some files.
Thanks (2 Replies)
I need to find out the last modified time for the files which are older than 6 months. If I use ls -l, the files which are older than 6 months, I am just getting the day, month and year instead of exact time. I am using Korn shell, and SUN OS.
Thanks in Advance,
Kiran (3 Replies)
Hi ,
I am trying to find out the List of files modified or added aftter installation of any component on SUN solaris box .
But i am not able to do it using ls or find command .
Can somebody help me out ?
Thanks
Sanjay Gupta (2 Replies)
Hi All,
I have a requirement to find out the files which are modified in the last 10 minutes.
I tried the find command with -amin and -mmin options, but its not working on my AIX server.
Can anyone of you could help me.
Thanks in advance for your help.
Raju (3 Replies)
Hi,
I want to modify a filename in AIX by attaching the last modified timestamp. I want the timestamp completely in numerical format (eg:200905081210. yr-2009, mnth - 05, date -08, hr - 12, mins - 10).
For example if the filename is a.log and it was modified on April 6th 2008 at 21.00. I... (16 Replies)
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Need help reading file last modified date in format:
Filename (relative path);YYYYMMDDHHMMSS
And then write it back. My idea is to backup it to a text file to restore later.
Checked this command but does not work:
Getting the Last Modification Timestamp of a File with Stat
$ stat -f... (5 Replies)
This should recursively walk through all dirictories and
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output manicured content (eg some regex) with CAT into
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one by one, keeping the original names
This is what I have so far, which seems to... (1 Reply)
Hi,
I would like use the output of my cut command as a variable in my following awk command. Here's what I've written.
cut -f1 info.txt | awk -v i=xargs -F'' '{if($6 == $i) print $20}' summary.txt
Where obviously the 'xargs' doesn't do what I want. How can I pass my cut result to my awk... (3 Replies)
Discussion started by: heyooo
3 Replies
LEARN ABOUT SUSE
grog
GROG(1) General Commands Manual GROG(1)NAME
grog - guess options for groff command
SYNOPSIS
grog [ -option ... ] [ files ... ]
DESCRIPTION
grog reads files and guesses which of the groff(1) options -e, -man, -me, -mm, -mom, -ms, -mdoc, -mdoc-old, -p, -R, -g, -G, -s, and -t are
required for printing files, and prints the groff command including those options on the standard output. A filename of - is taken to
refer to the standard input. If no files are specified the standard input will be read. Any specified options will be included in the
printed command. No space is allowed between options and their arguments. The only options recognized are -C (which is also passed on) to
enable compatibility mode, and -v to print the version number.
For example,
`grog -Tdvi paper.ms`
will guess the appropriate command to print paper.ms and then run it after adding the -Tdvi option.
SEE ALSO doctype(1), groff(1), troff(1), tbl(1), pic(1), eqn(1), refer(1), grn(1), grap(1), soelim(1)Groff Version 1.18.1 06 June 2002 GROG(1)