Sponsored Content
Top Forums Shell Programming and Scripting Print pattern regardless of space between Post 302769358 by elixir_sinari on Tuesday 12th of February 2013 03:53:30 AM
Old 02-12-2013
Code:
grep -i '^[ \t]*sshd[ \t]*:[ \t]*all[ \t]*:' file

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Find a pattern and print next all character to next space

Hi, I have a big inventory file that is NOT sorted is any way. The file is have "tagged" information like the ip address "*IP=" or the name "*NM=" . How do I get just the ip address or the name and not the whole line? I have tried to use AWK without any success. I always get the whole line... (8 Replies)
Discussion started by: pierrebjarnfelt
8 Replies

2. Shell Programming and Scripting

Print a pattern between the xml tags based on a search pattern

Hi all, I am trying to extract the values ( text between the xml tags) based on the Order Number. here is the sample input <?xml version="1.0" encoding="UTF-8"?> <NJCustomer> <Header> <MessageIdentifier>Y504173382</MessageIdentifier> ... (13 Replies)
Discussion started by: oky
13 Replies

3. Shell Programming and Scripting

Print characters till the next space when the pattern is found

i have a file which contains alphanumeric data in every line. what i need is the data after certain pattern. the data after the pattern is not of fixed length so i need the data till the space after the pattern. Input file: bfdkasfbdfg khffkf lkdhfhdf pattern (datarequired data not required)... (2 Replies)
Discussion started by: gpk_newbie
2 Replies

4. Shell Programming and Scripting

print lines up to pattern excluding pattern

11 22 33 44 55 66 77 When pattern 55 is met, print upto it, so output is 11 22 33 44 (1 Reply)
Discussion started by: anilcliff
1 Replies

5. Shell Programming and Scripting

Need one liner to search pattern and print everything expect 6 lines from where pattern match made

i need to search for a pattern from a big file and print everything expect the next 6 lines from where the pattern match was made. (8 Replies)
Discussion started by: chidori
8 Replies

6. Shell Programming and Scripting

Script to compare pattern and print a different pattern in each line

Hi, I am writing a shell script to parse some files, and gather data. The data in the files is displayed as below. .......xyz: abz: ......qrt: .... .......xyz: abz: ......qrt: ... I have tried using awk and cut, but the position of these values keep changing, so I wasn't able to get... (2 Replies)
Discussion started by: Serena
2 Replies

7. UNIX for Dummies Questions & Answers

Match Pattern after certain pattern and Print words next to Pattern

Hi experts , im new to Unix,AWK ,and im just not able to get this right. I need to match for some patterns if it matches I need to print the next few words to it.. I have only three such conditions to match… But I need to print only those words that comes after satisfying the first condition..... (2 Replies)
Discussion started by: 100bees
2 Replies

8. Shell Programming and Scripting

Match Pattern and print pattern and multiple lines into one line

Hello Experts , require help . See below output: File inputs ------------------------------------------ Server Host = mike id rl images allocated last updated density vimages expiration last read <------- STATUS ------->... (4 Replies)
Discussion started by: tigerhills
4 Replies

9. Shell Programming and Scripting

sed -- Find pattern -- print remainder -- plus lines up to pattern -- Minus pattern

The intended result should be : PDF converters 'empty line' gpdftext and pdftotext?xml version="1.0"?> xml:space="preserve"><note-content version="0.1" xmlns:/tomboy/link" xmlns:size="http://beatniksoftware.com/tomboy/size">PDF converters gpdftext and pdftotext</note-content>... (9 Replies)
Discussion started by: Klasform
9 Replies

10. Shell Programming and Scripting

Gawk --- produce the output in pattern space instead of END space

hi, I'm trying to calculate IP addresses and their respective calls to our apache Server. The standard format of the input is HOST IP DATE/TIME - - "GET/POST reuest" "User Agent" HOST IP DATE/TIME - - "GET/POST reuest" "User Agent" HOST IP DATE/TIME - - "GET/POST reuest" "User Agent" HOST... (2 Replies)
Discussion started by: busyboy
2 Replies
bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
All times are GMT -4. The time now is 02:21 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy