Here are a couple of ways to do what you want:
I use ksh and I added echo commands in several places so it will show what it will do rather than actually invoke mail to send messages. You'll need to change /bin/ksh in the first line of the script to the absolute pathname of a shell on your system that processes traditional Bourne shell command syntax (e.g., bash, ksh, or sh) to run the script and then remove echo from the awk printf() command after you verify that the script does what you want.
Choose whichever code segment you prefer to use. They both should do what you want. The first segment is a simplified and corrected version of what it looked like you were trying to do. The second one produces the same results, but should be more efficient.
These 2 Users Gave Thanks to Don Cragun For This Post:
Hi Guys,
I was just wondering if anybody can help me with this problem.
OK, how we can get a value back from PL/SQL Script (not stored procedure/function)
See the below example: (for example aaa.sh)
#!/bin/ksh
VALUE=`sqlplus -s user/password@test_id <<EOF
@xxx.sq
EOF`
echo $VALUE
... (7 Replies)
hi all,
Can any 1 help me translate this korn shell code to C shell code :
email=$(grep "^$1" $folder/config_2.txt | awk '{print $2'})
In config_2.txt the content is :
which mean in korn shell , $1=groupname and $2=email address.
Now i need to write in C shell script,when i set the... (2 Replies)
Hi,
I want to remove the following code from Source files (or replace the code with empty.) from all the source files in given directory.
finally {
if (null != hibernateSession && hibernateSession.isOpen()) {
//hibernateSession.close();
}
}
It would be great if the script has... (2 Replies)
Hi ,
I have a code where i am using a infinite while loop . some thing like below
while
do
if
then
#go to line 20
fi
command 1;
command 2;
#line 20:
sleep 34; (5 Replies)
Discussion started by: Paarth
5 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)