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Full Discussion: Help with code
Top Forums Shell Programming and Scripting Help with code Post 302753637 by Don Cragun on Wednesday 9th of January 2013 05:54:00 AM
Old 01-09-2013
Here are a couple of ways to do what you want:
Code:
#!/bin/ksh
echo simplififed translation from given code
while read i
do      grep $i /tmp/b | awk '{printf("echo mail -s \"%s is your new ID\" %s@companydomain.com", $2, $1)}' | ksh
done < /tmp/a

echo awk replacement
awk 'FNR == NR {
        newID[$1] = $2
        next
}
{       printf("echo mail -s \"%s is your new ID\" %s@companydomain.com\n",
                newID[$1], $1);
}' /tmp/b /tmp/a | ksh

I use ksh and I added echo commands in several places so it will show what it will do rather than actually invoke mail to send messages. You'll need to change /bin/ksh in the first line of the script to the absolute pathname of a shell on your system that processes traditional Bourne shell command syntax (e.g., bash, ksh, or sh) to run the script and then remove echo from the awk printf() command after you verify that the script does what you want.

Choose whichever code segment you prefer to use. They both should do what you want. The first segment is a simplified and corrected version of what it looked like you were trying to do. The second one produces the same results, but should be more efficient.
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bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
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