I write a sh script that zip and copy to tape all files that older then 2 hours.
1. The way I choose is - touch a file with "now - 2 hours", then use fine with '! -newer'
2. Do you have any other idea to do it ?
tnx. (1 Reply)
I Have a long file like this
123122312 05/06/12
123123456 05/06/14
I want to take the difference of dates in two lines & print difference sidewise for the whole long files.
Pl help me out. (1 Reply)
I have the script which appends month and year to the name of the
file. Now every time when I append the month-year combination I
have to subtract 2 months from the current date and then append
it, since we are sending our vendor 2 months prior worth of data
eveytime.
#! /usr/bin/ksh
... (5 Replies)
the given time is:
12:13:00
how do i subtract a 10 minutes from any given time?
date '12:13:00' '-10 min'
also tried this:
date +12:13:00 '-10 min' (2 Replies)
I have a file with name and date---
$ cat file.log
userA 01-06-2014
userB 25-05-2014
userC 16-05-2014
userC 01-03-2014
I want to search for the current date and get the name for that date. If current date is not found, go back 1 day and search and so on till it finds the... (2 Replies)
Hi,
I am reading a particular date from a file using below command
WFLWDATE=$(sed '2q;d' FileA.prm)
The echo command outputs the correct date in variable WFLWDATE
Now I want to subtract 5 minutes from this variable. I am on AIX and unable to get anything working as expected.
Can you... (1 Reply)
Hi,
Can you please let me know code for the below (in korn shell)
a) Subtract month(s) from given date
b) Subtract day(s) from give date
c) Subtract month(s) from given timestamp
d) Subtract day(s) from give timestamp (1 Reply)
SunOS -s 5.10 Generic_147440-04 sun4u sparc SUNW,SPARC-Enterprise
Hi,
In a folder, there are files. I have a script which reads the current date and subtract the modification date of each file.
How do I achieve this?
Regards,
Joe (2 Replies)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT MOJAVE
date::parse
Date::Parse(3) User Contributed Perl Documentation Date::Parse(3)NAME
Date::Parse - Parse date strings into time values
SYNOPSIS
use Date::Parse;
$time = str2time($date);
($ss,$mm,$hh,$day,$month,$year,$zone) = strptime($date);
DESCRIPTION
"Date::Parse" provides two routines for parsing date strings into time values.
str2time(DATE [, ZONE])
"str2time" parses "DATE" and returns a unix time value, or undef upon failure. "ZONE", if given, specifies the timezone to assume when
parsing if the date string does not specify a timezone.
strptime(DATE [, ZONE])
"strptime" takes the same arguments as str2time but returns an array of values "($ss,$mm,$hh,$day,$month,$year,$zone)". Elements are
only defined if they could be extracted from the date string. The $zone element is the timezone offset in seconds from GMT. An empty
array is returned upon failure.
MULTI-LANGUAGE SUPPORT
Date::Parse is capable of parsing dates in several languages, these include English, French, German and Italian.
$lang = Date::Language->new('German');
$lang->str2time("25 Jun 1996 21:09:55 +0100");
EXAMPLE DATES
Below is a sample list of dates that are known to be parsable with Date::Parse
1995:01:24T09:08:17.1823213 ISO-8601
1995-01-24T09:08:17.1823213
Wed, 16 Jun 94 07:29:35 CST Comma and day name are optional
Thu, 13 Oct 94 10:13:13 -0700
Wed, 9 Nov 1994 09:50:32 -0500 (EST) Text in ()'s will be ignored.
21 dec 17:05 Will be parsed in the current time zone
21-dec 17:05
21/dec 17:05
21/dec/93 17:05
1999 10:02:18 "GMT"
16 Nov 94 22:28:20 PST
LIMITATION
Date::Parse uses Time::Local internally, so is limited to only parsing dates which result in valid values for Time::Local::timelocal. This
generally means dates between 1901-12-17 00:00:00 GMT and 2038-01-16 23:59:59 GMT
BUGS
When both the month and the date are specified in the date as numbers they are always parsed assuming that the month number comes before
the date. This is the usual format used in American dates.
The reason why it is like this and not dynamic is that it must be deterministic. Several people have suggested using the current locale,
but this will not work as the date being parsed may not be in the format of the current locale.
My plans to address this, which will be in a future release, is to allow the programmer to state what order they want these values parsed
in.
AUTHOR
Graham Barr <gbarr@pobox.com>
COPYRIGHT
Copyright (c) 1995-2009 Graham Barr. This program is free software; you can redistribute it and/or modify it under the same terms as Perl
itself.
POD ERRORS
Hey! The above document had some coding errors, which are explained below:
Around line 325:
You forgot a '=back' before '=head1'
perl v5.18.2 2009-12-12 Date::Parse(3)