I try to use the pattern substitution operators as documented in the O'Reilley "Learning the Korn Shell" but it doesn't seem to work as advertised.
This works all right:
The docs says that using !(expr) matches anything that does't match expr but if I try to replace all but the "e" character, it does not seem to work:
Any idea?
Hi,
I have file 1.txt with following entries as shown:
0152364|134444|10.20.30.40|015236433
0233654|122555|10.20.30.50|023365433
**
**
**
In file 2.txt I have the following entries as shown:
0152364|134444|10.20.30.40|015236433
0233654|122555|10.20.30.50|023365433... (4 Replies)
Hi all,
I'm looking for some help. I have a file (very long) that is organized like below:
>Cluster 0
0 283nt, >01_FRYJ6ZM12HMXZS... at +/99%
1 279nt, >01_FRYJ6ZM12HN12A... at +/99%
2 281nt, >01_FRYJ6ZM12HM4TS... at +/99%
3 283nt, >01_FRYJ6ZM12HM946... at +/99%
4 279nt,... (4 Replies)
All,
I have the following file:
--------------------------------------
#
# /etc/pam.d/common-password - password-related modules common to all services
#
# This file is included from other service-specific PAM config files,
# and should contain a list of modules that define the services... (2 Replies)
I figured this would be simple, but I am stuck.
Variable longpath="/dir1/dir2/dir3/filename.stuff.morestuff.garbage"
I want to end up with just "filename.extra.moreextra". So, I want to get rid of the path and .garbage
I want to do this with just ksh internals. So, no sed,grep,awk,expr,... (4 Replies)
Hi,
I am trying to get a result out of this but fails please help. Have two files /tmp/1 & /tmp/hosts.
/tmp/1
IP=123.456.789.01
WAS_HOSTNAME=abcdefgh.was.tb.dsdc
/tmp/hosts
123.456.789.01
I want this result in /tmp/hosts if hostname is already there dont want duplicate entry.
... (5 Replies)
'Hi
I'm using the following code to extract the lines(and redirect them to a txt file) after the pattern match. But the output is inclusive of the line with pattern match.
Which option is to be used to exclude the line containing the pattern?
sed -n '/Conn.*User/,$p' > consumers.txt (11 Replies)
The sample file:
dept1: user1,user2,user3
dept2: user4,user5,user6
dept3: user7,user8,user9
I want to match by '/^dept2.*/' but don't want to have substring 'dept2:' in output. How to compose such regex? (8 Replies)
Hi all!
Thanks for taking the time to view this!
I want to grep out all lines of a file that starts with pattern 1 but also does not match with the second pattern.
Example:
Drink a soda
Eat a banana
Eat multiple bananas
Drink an apple juice
Eat an apple
Eat multiple apples
I... (8 Replies)
Hi
I need to do a patten match between files .
I am new to shell scripting and have come up with this so far. It take 50 seconds to process files of 2mb size . I need to tune this code as file size will be around 50mb and need to save time.
Main issue is that I need to search the pattern from... (2 Replies)
Discussion started by: nitin_daharwal
2 Replies
LEARN ABOUT BSD
expr
EXPR(1) General Commands Manual EXPR(1)NAME
expr - evaluate arguments as an expression
SYNOPSIS
expr arg ...
DESCRIPTION
The arguments are taken as an expression. After evaluation, the result is written on the standard output. Each token of the expression is
a separate argument.
The operators and keywords are listed below. The list is in order of increasing precedence, with equal precedence operators grouped.
expr | expr
yields the first expr if it is neither null nor `0', otherwise yields the second expr.
expr & expr
yields the first expr if neither expr is null or `0', otherwise yields `0'.
expr relop expr
where relop is one of < <= = != >= >, yields `1' if the indicated comparison is true, `0' if false. The comparison is numeric if
both expr are integers, otherwise lexicographic.
expr + expr
expr - expr
addition or subtraction of the arguments.
expr * expr
expr / expr
expr % expr
multiplication, division, or remainder of the arguments.
expr : expr
The matching operator compares the string first argument with the regular expression second argument; regular expression syntax is
the same as that of ed(1). The (...) pattern symbols can be used to select a portion of the first argument. Otherwise, the
matching operator yields the number of characters matched (`0' on failure).
( expr )
parentheses for grouping.
Examples:
To add 1 to the Shell variable a:
a=`expr $a + 1`
To find the filename part (least significant part) of the pathname stored in variable a, which may or may not contain `/':
expr $a : '.*/(.*)' '|' $a
Note the quoted Shell metacharacters.
SEE ALSO sh(1), test(1)DIAGNOSTICS
Expr returns the following exit codes:
0 if the expression is neither null nor `0',
1 if the expression is null or `0',
2 for invalid expressions.
7th Edition April 29, 1985 EXPR(1)