UNIX for Dummies Questions & Answers

Hi,

I am a new bie to unix shell programming. I have specified ksh as the first line in my script but when executed it complains.

*********** Script=test********************
#!/usr/bin/ksh

echo hello

print -p 123
************************************

++++++++ Execution results+++++++++++++++
Prompt# . ./test
hello
bash: print: command not found
++++++++++++++++++++++++++++++++++++


I have ran "which ksh" and it points to /usr/bin/ksh

I am not sure why it still executs the script in bash as it seems from the execution results.

Please help,
Akhil

print -p 123

wat ru exactly tryin with above statement...

You're sourcing the script with the dot builtin,
try executing it like this:

Code:

./test

Do not run dot dot slash script name, but only dot slash script name.

Thanks a ton.

What is the difference?

If you source the script (using the source or the dot '.' builtins) the code is executed in the current shell (bash in your case) and the shebang (the first two characters in the file: #!) is ignored.

It is still complaining with this error

*******************
Prompt # ./test
hello
./test[5]: print: no query process
********************

Thanks for your help,
Akhil

It's because you're trying to communicate with a nonexistent co-process. Try using print, instead of print -p.