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Help with grepping and line number

 
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Top Forums UNIX for Dummies Questions & Answers Help with grepping and line number
# 1  
Old 12-28-2008
Question Help with grepping and line number
I need help with extracting data from a large file ~900mb. Below is how the data looks like,
line number value
1001 10000
... ...
5001 50000
6001 60000
... ...
10001 100000
... ...
100001 1000000
basically i need to grep lines starting from line 1001 and keep grepping line data for every 1000 after that. this is because after a certain number of lines ******** is displayed for the values which is problematic for my usual grepping scheme and hence my need to use the grep line number method. any help on the command for doing this would be much appreciatedSmilie
# 2  
Old 12-29-2008
Try this:

Code:
awk '{ if ($1 ~ /[0-9]*001/) print; }'  file

# 3  
Old 12-29-2008
i have used the following code previously,
less a.dat | grep ".[0-9][0-9][0-9]0000..." > x.dat
which had worked very well previously but now need to take line number into consideration. is there a command similar to this?Smilie
# 4  
Old 12-29-2008
Question
Quote:
Originally Posted by dennis.jacob
Try this:

Code:
awk '{ if ($1 ~ /[0-9]*001/) print; }'  file

the following is what is output using your code,

...
400160 0.13202E-05 0.37790E-15 7732 -0.83922E-05 0.84854E-05
400170 0.13202E-05 0.38622E-15 7732 -0.83929E-05 0.84873E-05
400180 0.13202E-05 0.40112E-15 7731 -0.83933E-05 0.84888E-05
400190 0.13203E-05 0.41872E-15 7732 -0.83918E-05 0.84899E-05
410010 0.13527E-05 0.36685E-15 7730 -0.82925E-05 0.85203E-05
420010 0.13857E-05 0.30460E-15 7728 -0.83042E-05
...

i would like the bold part to be kept as 0000 and the remaining part before the zeroes to increment as usual [0-9]...
unfortunately did'nt work, but maybe useful code needing a bit of a tweak. thanks anyway.
 
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