Tree directory structure of Unix to get final node path


 
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# 1  
Old 12-18-2008
Tree directory structure of Unix to get final node path

Hi,

I want to list all the last directories from mentioned base path.

for eg: If i have a base path say /base/base1/

How can i get the path till last node in tree like directory structure of unix by applying any command.
so that i will get following output.

/base/base1/base2/final1/final2/last
/base/base1/base2/final1/final3/last
/base/base1/base2/final1/last
/base/base1/base2/final1/final4/last
# 2  
Old 12-18-2008
Code:
find /base/base1 -type d -name "last" -print

# 3  
Old 12-18-2008
In short i want all the possible unique longest paths under base dir
# 4  
Old 12-18-2008
Its not necessary the last node is always "last"
# 5  
Old 12-18-2008
Did you try it out at least? Or do I misunderstand Smilie

Code:
root@isau02:/data/tmp/testfeld> find bla -type d -print
bla
bla/yoyo
bla/yoyo/last
bla/yoyo/last/some
root@isau02:/data/tmp/testfeld> find bla -type d -name last -print
bla/yoyo/last
root@isau02:/data/tmp/testfeld>

# 6  
Old 12-18-2008
In the above directory structure mentioned by you I want only "bla/yoyo/last/some" to be printed.

i.e The longest unique path. Here the last node is "some". I hope it clears now.
# 7  
Old 12-18-2008
A directory with no subdirectories contains only two directories "." and "..".

Code:
#!/bin/ksh
find /base/base1/ -type d -print|sort|while read DIR
do
        DIR_COUNT=`ls -la "${DIR}"|grep \^d|wc -l`
        if [ ${DIR_COUNT} -eq 2 ]
        then
                echo "${DIR}"
        fi
done

 
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