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Help to extract the content in this string

 
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# 1  
Old 11-25-2008
Help to extract the content in this string
Hi All,

I have a string in the following format:
"kf skjgsdjgngnsd sdgsd

ksjgbksjgb kjsbgsjdgb
dfhdh

sjgsjg j jsbekgjsbdkgj".

In this format i want to extract the contents which is in between the two empty lines: i.e, i want to extract the following
"ksjgbksjgb kjsbgsjdgb
dfhdh ".

Please help me in this. Thanks in advance.

Regards,
Bala
# 2  
Old 11-25-2008
What did you try so far?

Code:
sed -n '/^$/,/^$/ {/^[^ ]/p}' infile
ksjgbksjgb kjsbgsjdgb
dfhdh

Last edited by zaxxon; 11-25-2008 at 02:01 AM.. Reason: Corrected a little error
# 3  
Old 11-25-2008
Hi,
I'm a beginer in UNIX. I have tried using cut with regular expressions. but that doesnt work.The Problem is i'll not be having the string in a file. It comes out of some other operations and the format of that o\p is as given below in the previous post.
can u please explain me the command u gave, what is the use of that infile. The String will be dynamic. it can be anything but only the pattern will be same. That is i have to extract all the string between two new lines.

Thanks in advance,
Bala
# 4  
Old 11-25-2008
You should be able to pipe your output just into that sed command.
infile is just the filename I saved your example on my harddisk and I feed sed not with a pipe in front of it but just with this infile.

If the output you want to parse varies a lot, you can't go like that. You have to know how your output looks as close as possible.

Code:
sed -n              # Print only the stuff we want to see; else it prints all 
                    # the stuff it is processing additionally
'                   # Here starts the regex and commands
/^$/,/^$/           # The / starts and ends a pattern; ^ is the start of a
                    # line, $ the end of a line and since nothing is specified 
                    # between it, it must be an empty line. So writing two 
                    # patterns separated with a comma is like giving a 
                    # range "from" "to"
{/^[^ ]/p}          # When the range is separated, do the command in curled
                    # braces. The command inside the braces says to get a
                    # pattern, that does not start with a blank. Inside square brackets the ^ means "not". The p simply stands for print.


' infile

# 5  
Old 11-25-2008
Hi,
I tried the following thing.
comment1 = $(echo "$comment1" | sed -n '/^$/,/^$/ {/[^ ]/p}').

where comment1 has the string which shuld be formatted. But it's saying that:
sed: command garbled: /^$/,/^$/ {/[^ ]/p}.

Is there anything wrong with the regex we are using.

Regards,
Bala
# 6  
Old 11-25-2008
I am not sure what you are going to do. If you echo "$comment1", what do you get? Is the output you want to parse in a variable? If it is just the output of a command, try using that command and put a pipe | behind that command followed by the sed command. If it is a file, use it as I did above. If there is no reason to force the text into a variable, don't do it.
# 7  
Old 11-25-2008
try saving that string to a file.its easier that way even though you have to create a file.

you can then use:

string = `more <filename>`

then use the string variable to extract that text with the sed command.

you can always delete the file once you are done with rm.
 
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