Piping syntax question


 
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# 1  
Old 11-20-2008
Piping syntax question

There are are lots of examples of piping output FROM the 'ls' command TO another command, but how does one pipe output TO the 'ls -l' command?

For example, use 'which' to find a file, then use 'ls -l' to view the permissions, groups, etc. in a single step:

which <filename> | ls -l

returns a long listing of the current directory, not a long listing of the filename and path returned by the 'which' command.

which <filename> | ls -l -

returns a file not found error on '-'

Suggestions, please. Thanks!

John
# 2  
Old 11-20-2008
Code:
ls -l `which <filename>`

# 3  
Old 11-20-2008
Thanks, Ikon!
# 4  
Old 11-20-2008
Code:
a=$(which filename) && ls -l $a

# 5  
Old 11-20-2008
Quote:
Originally Posted by jlliagre
Code:
a=$(which filename) && ls -l $a

Thanks for that alternate solution, jlliagre!

That's better than my idea of doing the same thing with multiple commands on a single commandline with a command separator between them.
 
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