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Distinct search usisng GREP cmd

 
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# 1  
Old 11-14-2008
Distinct search usisng GREP cmd
Hi All,

I have the following problem where I have been trying but not able to resolve it:-

I have a file which has some thousands entries.
For eg:-
The content of the file is :-
==============================================

./admin.cpp:9:#include "framework/RegistryContext.h"
./admin.cpp:10:#include "framework/LoggingContext.h"
./adminbatchbase.h:10:#include"framework/RegistryInterface.h"
./adminbatchbase.h:11:#include"framework/LoggingInterface.h"
./adminbatchbase.h:12:#include"framework/BatchException.h"

===============================================

Now if I count the number of occurences of "framework" then it comes to 5(wc -l)
But I want the count to be 2 as there are only 2 distinct files where framework is there.

Could somebdy help me with this?

Thanks,
SD.
# 2  
Old 11-14-2008
Sorry....The below code will not work as per the requirement Smilie

Try using -w option with grep. If you want the search to be extended in multiple files, try the following command

find . 2>/dev/null | xargs grep -w "string" 2>/dev/null
Last edited by sriharsha_kvr; 11-14-2008 at 05:27 AM.. Reason: Requirement wrongly understood
# 3  
Old 11-14-2008
This should work

find . 2>/dev/null | xargs grep -w framework | cut -d ":" -f1 | uniq -d
 
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