UNIX for Dummies Questions & Answers

Hi All,

Appreciate if anyone can help. I've a script where it does echo function like this

while [ $w -lt $CNT ]
do
FILE_ARG="cu0${w}_${FILE}_${DT}.av"

ORACLE_ERROR=`grep "ORA-" ${FILE_ARG}`
if [[ ${ORACLE_ERROR} != "" ]]; then
Func_Log_Writer "Fail! ${FILE_ARG}\n"
Func_Log_Writer "Error message: ${ORACLE_ERROR}\n"
Func_Exit 1
fi

w=`expr $w + 1`

if [ $w -eq $CNT ]; then
echo "0"
return 0
fi
done

However, when the message print to screen, it return in one line though i've include \n.

Output from script:

./DM_val_procedure_test.ksh[286]: [2008-11-05 16:35:35] Error message: ORA-12154: TNS:could not resolve service name^J[2008-11-05 16:35:35] Return code of validation is 1^J[2008-11-05 16:35:36] Terminated application!^J1: Syntax error

The ^J is the \n character you put in the echo statement.
You will have to change the way you write to stdout.

Where is the code that actually does the echo? I gather it is a function called Func_Log_Writer - please post that.

Try this contruct to process each error message in turn:

grep "ORA-" ${FILE_ARG} | while read ORACLE_ERROR
do
# Process each error message in ORACLE_ERROR
done