UNIX for Dummies Questions & Answers

Hello All,

1.)
I am searching for ".exe" in a text file

2.)
I need to search for a hexadecimal entree of at least four digits

1: grep for '.exe':

Code:

grep -w '.exe'

2: Use egrep:

Code:

egrep -w '0x[0-9]+{4,}'

Regards

when i did "grep -w '.exe'" then the file name, it turned out 0 results but i know there are a few there.

When i did
egrep -w '0x[0-9]+{4,}' I also get 0 results. the four digits after the 0x can consist of Upper or Lowercase letters A-F or numbers 0-9

Here are the original problems. I have a .txt file and using grep i need to do this.
# Look for executable file names (i.e. ending with an .exe).
# Note the line numbers in the file where a hexadecimal entree of at least four digits occurs. Hexadecimal numbers are denoted by the prefix 0x, and their "digits" are either 0-9 or A-F. For example, 0x7A89 is a four digit hexadecimal number.

How does a line with '.exe' looks like?

Assuming you also have lower-case hex letters:

Code:

egrep -w '0x[0-9A-Fa-f]+{4,}'

Regards

i type
grep -w '.exe' i* and i get nothing returned.

when i type
grep -w 'exe' i* i get both .exe and exe. I need to eliminate the plain exe

It works fine with my version of grep, try to escape the dot:

Code:

grep -w '\.exe' i*

Regards

Thanks that worked.

~Thanks