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How to grep a particular pattern using a variable

 
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# 1  
Old 09-02-2008
How to grep a particular pattern using a variable
Hi all,

I am searching for the files with a pattern which is stored in a variable.
eg:
the day is taken from the date format into a variable "day"
I am trying to search with the pattern in that variable.

ls -ltr | grep "$day"

I am not getting the filtered output.

Please help me in how to search for the pattern which is in a variable.

Thanks,
ladtony
# 2  
Old 09-02-2008
this should work.

try echoing the contents of day
Code:
echo $day

that should give an idea on whats going wrong
# 3  
Old 09-02-2008
am doing an echo
but how to use that in a grep
ls -ltr | grep "$day" is not working
ladtony
# 4  
Old 09-02-2008
if possible show us the contents of ls -ltr

and echo $day
# 5  
Old 09-02-2008
i cant give u the output as its very huge
its giving all the files with the other days also..
echo $day :
output : 02
ladtony
# 6  
Old 09-02-2008
I have made a little change and am getting the output but if the date is Sep 2 then if am searching for that using the variable then am getting the output as all the files which contain sep 2
eg :
Sep 23
Sep 24 etc.,
ladtony
# 7  
Old 09-03-2008
Quote:
Originally Posted by ladtony
i cant give u the output as its very huge
its giving all the files with the other days also..
echo $day :
output : 02
I didn't mean to dump the actual source file as such

I was expecting something like,

sample input
&
sample output
 
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