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How to grep a particular pattern using a variable

 
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# 8  
Old 09-03-2008
Question How to grep a particular pattern using a variable
hi ...
sample input:
path ="/dir/sample" :we have the files as
abcab-a-c 1 user xxx filesize month date filename
abcab-a-c 1 user xxx filesize month1 date1 filename
abcab-a-c 1 user xxx filesize month date filename
abcab-a-c 1 user xxx filesize month1 date1 filename
abcab-a-c 1 user xxx filesize month date filename
abcab-a-c 1 user xxx filesize month date filename

desired output for command
cd $path
ls -ltr | grep "$day" >samplefile -----(where $day=month1 date1)
abcab-a-c 1 user xxx filesize month1 date1 filename
abcab-a-c 1 user xxx filesize month1 date1 filename

Thanks,
ladtony
# 9  
Old 09-03-2008
hi ...
sample input:
path ="/dir/sample" :we have the files as
abcab-a-c 1 user xxx filesize month date filename
abcab-a-c 1 user xxx filesize month1 date1 filename
abcab-a-c 1 user xxx filesize month date filename
abcab-a-c 1 user xxx filesize month1 date1 filename
abcab-a-c 1 user xxx filesize month date filename
abcab-a-c 1 user xxx filesize month date filename

desired output for command
cd $path
ls -ltr | grep "$day" >samplefile -----(where $day=month1 date1)
abcab-a-c 1 user xxx filesize month1 date1 filename
abcab-a-c 1 user xxx filesize month1 date1 filename

Thanks,
ladtony
 
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