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size of number variable in unix (awk)


 
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# 1  
Old 08-19-2008
Lightbulb size of number variable in unix (awk)

Hi All,

M writing a shell scripting n making use of awk. I am using a integer variable named size. When printing it's value, it is giving result as 4.34534e+10.

Is there any way to declare variable of type LONG in awk or in shell scripting in general ?


Regards,
Abhishek Gera
# 2  
Old 08-19-2008
I have got one way to use printf and force the size to be of length 10. But still let me know other possible ways
# 3  
Old 08-19-2008
awk uses double precision floating point numbers for arithmetic operations. printf with format is the only good choice. There is no datatype cast available in awk. So basically you already found the best way to solve the problem.
# 4  
Old 04-01-2009
Bug Here is the possible answer to this

In awk we can use the printf function as we use that in C.
e.g. echo 7894561213563.21|awk 'BEGIN{c=0;} {c=c+$0} END{printf("%lf\n",c);}' will print the sum in double format.
 

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