UNIX for Dummies Questions & Answers

Hi

Im trying to syncronise 4 webserver mirrors, using the rsync command. /www/html is the html documents directory.

i am using


export RSYNC_RSH="/usr/local/bin/ssh -l $REMOTE_USER"
rsyn -va /www/html remotehost:/www/html

when this is run, it copies the html file over to the remote server using ssh as expected. but it creates a second html directory. eg
/www/html/html. and places the html files in there

any ideas why this is happening and not putting the html files in /www/html.


thanks

Stu

Have you tried the following:

export RSYNC_RSH="/usr/local/bin/ssh -l $REMOTE_USER"
rsyn -va /www/html remotehost:/www

Hi

no havent tried that, Its a bit more complicated actualy. its a script that reads a list of directorys from a text file and loops through them all, and gets a $source_file which is also the destination variable.
so the command is actualy

rsync -va $source_file $remote_host@$source_file

if i echo this line i get

rsyn -va /www/html webserver1:/www/html

my question really, is the above syntax correct?

to try what you suggest i would need to do something like

$source_file == $dest_path

and then strip the last directory off the $dest_path

hhmm anyone know how to do that?

If you are using a korn shell script you could do the following

#!/bin/ksh -f

source_file="/www/html"

dest_path=${source_file%/*}

echo "source file = " $source_file
echo "dest_path = " $dest_path

which will give you:
source file = /www/html
dest_path = /www