replace the n'th occurance in a file


 
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# 1  
Old 06-04-2008
replace the n'th occurance in a file

Hi All,

How can i replace the n'th occurance in a file. ?
I have a property file like

EAR;_TrackingEAR;META-INF/application.xml;xml;context-root;1;valeur
EAR;_TrackingEAR;META-INF/application.xml;xml;context-root;2;valeur2
EAR;_TrackingEAR;META-INF/application.xml;xml;context-root;3;valeur2


i need to replace the <context-root> tag value in the application.xml file with new value valeur,valeur2 etc
1 means update the first occurance with valeur,
2 means second occurance with valeur2
3 for third occurance ...

How can i do this using sed or any other command ??

Thanks in advance

Subin
# 2  
Old 06-04-2008
Something like this?

Code:
awk 'BEGIN{FS=OFS=";"}{$7="valeur"$6}1' file

Regards
# 3  
Old 06-04-2008
I don't think you got wat i really want,

to be more precise

i have an xml file specified in that file i need to put the value provided in tha last field to the tag provided and 1 says that i need to put the value in the first occurance and 2 says that i need to put the value in the second occurrance

property file is just the input file... i need to replcae the changes in the xml file

Thanks in Advance
subin
 
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