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Converting bash shell to perl

 
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# 1  
Old 05-28-2008
Converting bash shell to perl
Does anyone know how to convert this bash shell script to perl?
Code:
for i in `ls -l *pgp`
do
`usr/bin/gpg --passphrase-fd 0 $i < .sunspot`
done

Thanks! Any help would be appreciated. I'm new to Linux and perl.
Last edited by Yogesh Sawant; 05-28-2008 at 12:11 PM.. Reason: added code tags
# 2  
Old 05-28-2008
try this:
Code:
$some_dir = "/path/to/dir";
opendir(PGP_DIR, $some_dir) || die "can't opendir $some_dir: $!";
@pgp_files = grep { /pgp$/ && -f "$some_dir/$_" } readdir(PGP_DIR);
closedir(PGP_DIR);

for my $pgp_file (@pgp_files) {
    my @output = `usr/bin/gpg --passphrase-fd 0 $pgp_file < .sunspot`;
}

# 3  
Old 05-28-2008
Thank you very much
Thank you so much Mr. Sawant!
# 4  
Old 05-28-2008
Another bash shell to perl conversion
Hello everyone. I am new to linux and need help again. I need help converting this bash shell to linux:

for i in `ls -l *.txt`
do
`./cnvidtf.pl $i`
`curl -u loginSmilieswd --disable-espv -T loadfile.seq ftp://11.1.11.1`
`mysql -u login -h 11.1.11.1 -ppswd < lddocs.sql`
done

Thanks! Any help would be greatly appreciated.
Last edited by freak; 05-28-2008 at 08:20 PM.. Reason: Smiley face in middle of code
# 5  
Old 05-29-2008
Quote:
Originally Posted by freak
Hello everyone. I am new to linux and need help again. I need help converting this bash shell to linux:

for i in `ls -l *.txt`
do
`./cnvidtf.pl $i`
`curl -u loginSmilieswd --disable-espv -T loadfile.seq ftp://11.1.11.1`
`mysql -u login -h 11.1.11.1 -ppswd < lddocs.sql`
done

Thanks! Any help would be greatly appreciated.
please ask new question in a new thread

Edit: i see that you have started a new thread here. closing this thread
Last edited by Yogesh Sawant; 05-29-2008 at 01:54 AM..
 
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