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Using sed to print a ruler

 
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# 1  
Old 05-03-2008
Using sed to print a ruler
How can I use sed to print rulers of x characters in length on my terminal?

For example, I want sed to print a 50-character rule.

sed '/[1-50]/ p' ??

Thanks!
# 2  
Old 05-03-2008
Code:
sed 's/\(.\{50\}\).*/\1/' file

Regards
# 3  
Old 05-03-2008
Thank you - what should be in the file then?
# 4  
Old 05-03-2008
I think I misunderstood your question, the sed command prints the first 50 characters of a line.
To print a line of 50 'x' you can use awk:

Code:
awk 'BEGIN{$50=OFS="x";print}'

Regards
# 5  
Old 05-04-2008
With some shells (recent versions of bash, zsh):

Code:
printf '#%.0s' {1..50}

# 6  
Old 05-04-2008
Thanks guys!!
 
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